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  • UVa 400 Unix ls 命令

    UVA 400
    The computer company you work for is introducing a brand new computer line and is developing a
    new Unix-like operating system to be introduced along with the new computer. Your assignment is to
    write the formatter for the ls function.
    Your program will eventually read input from a pipe (although for now your program will read
    from the input file). Input to your program will consist of a list of (F) filenames that you will sort
    (ascending based on the ASCII character values) and format into (C) columns based on the length (L)
    of the longest filename. Filenames will be between 1 and 60 (inclusive) characters in length and will be
    formatted into left-justified columns. The rightmost column will be the width of the longest filename
    and all other columns will be the width of the longest filename plus 2. There will be as many columns
    as will fit in 60 characters. Your program should use as few rows (R) as possible with rows being filled
    to capacity from left to right.
    Input
    The input file will contain an indefinite number of lists of filenames. Each list will begin with a line
    containing a single integer (1 ≤ N ≤ 100). There will then be N lines each containing one left-justified
    filename and the entire line’s contents (between 1 and 60 characters) are considered to be part of the
    filename. Allowable characters are alphanumeric (a to z, A to Z, and 0 to 9) and from the following set
    {._-} (not including the curly braces). There will be no illegal characters in any of the filenames and
    no line will be completely empty.
    Immediately following the last filename will be the N for the next set or the end of file. You should
    read and format all sets in the input file.
    Output
    For each set of filenames you should print a line of exactly 60 dashes (-) followed by the formatted
    columns of filenames. The sorted filenames 1 to R will be listed down column 1; filenames R + 1 to 2R
    listed down column 2; etc.
    Sample Input
    10
    tiny
    2short4me
    very_long_file_name
    shorter
    size-1
    size2
    size3
    much_longer_name
    12345678.123
    mid_size_name
    12
    Weaser
    Alfalfa
    Stimey
    Buckwheat
    Porky
    Joe
    Darla
    Cotton
    Butch
    Froggy
    Mrs_Crabapple
    P.D.
    19
    Mr._French
    Jody
    Buffy
    Sissy
    Keith
    Danny
    Lori
    Chris
    Shirley
    Marsha
    Jan
    Cindy
    Carol
    Mike
    Greg
    Peter
    Bobby
    Alice
    Ruben
    Sample Output

    题目很长,题意大致是 先输入一个正整数n,后面是n个文件名,排序后按列优先的方式左对齐输出。假设最长的文件名有M个字符,则最右列有M字符,其他列都是M+2字符。

    #include<iostream>
    #include<algorithm>
    #include<cstring>
    #include<cstdio>
    using namespace std;
    const int maxcol=60;
    const int maxn=105;
    string filenames[maxn];
    void print(const string &s,int len,char extra)
    {
        cout<<s;
        for(int i=0;i<len-s.length();i++)
        {
            cout<<extra;
        }
    }
    int main()
    {
        int n;
        while(cin>>n)
        {
            int m=0;
            for(int i=0;i<n;i++)
            {
                cin>>filenames[i];
                m=max(m,(int)filenames[i].length());
            }
            int cols=(maxcol-m)/(m+2)+1,rows=(n-1)/cols+1;
            print("",60,'-');
            cout<<"
    ";
            sort(filenames,filenames+n);
            for(int r=0;r<rows;r++)
            {
                for(int c=0;c<cols;c++)
                {
                    int idx=c*rows+r;
                    if(idx<n)
                        print(filenames[idx],c==cols-1?m:m+2,' ');
                }
                cout<<endl;
            }
        }
        return 0;
    }
    
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  • 原文地址:https://www.cnblogs.com/nanfenggu/p/7900103.html
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