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  • 二柱子的出题软件

    二柱子的软件

    支持真分数的四则运算

    可定义出题数量

    #define _CRT_SECURE_NO_DEPRECATE
    #include<stdio.h>
    #include<Windows.h>
    #include<time.h>
    int main()
    {
     int a, b, c, d, e, f, g, k;
     float p, q;
     printf("请输入想要の数量");
     scanf("%d",&k);
     srand(unsigned(time(NULL)));
     for (e = 0; e < k; e++)
     {
      a = rand() % 100;
      b = rand() % 100;
      c = rand() % 5;
      switch (c)
      {
      case 0: printf("第%d题:%d + %d = ",e+1, a, b);
       break;
      case 1:if (a < b)
      {
       d = a;
       a = b;
       b = d;
      }
          printf("第%d题:%d - %d = ",e+1, a, b);
          break;
      case 2:printf("第%d题:%d * %d = ",e+1, a, b);
       break;
      case 3:
       while (b == 0)
       {
        b = rand() % 100;
       }
       printf("第%d题:%d / %d = ",e+1, a, b);
       break;
      case 4:
       a = rand() % 100;
       b = rand() % 100;
       f = rand() % 100;
       g = rand() % 100;
       c = rand() % 4;
       while (b == 0)
       {
        b = rand() % 100;
       }
       while (g == 0)
       {
        g = rand() % 100;
       }
       if (a > b)
       {
        d = a;
        a = b;
        b = d;
       }
       if (f > g)
       {
        d = f;
        f = g;
        g = d;
       }
       switch (c)
       {
       case 0:printf("第%d题:%d/%d + %d/%d = ",e+1, a, b, f, g);
        break;
       case 1:
        p = (float)a / (float)b;
        q = (float)f / (float)g;
        if (p < q)
        {
         d = a;
         a = f;
         f = d;
         d = b;
         b = g;
         g = d;
        }
        printf("第%d题:%d/%d - %d/%d = ",e+1, a, b, f, g);
        break;
       case 2:printf("第%d题:%d/%d * %d/%d = ",e+1, a, b, f, g);
        break;
       case 3:
        a = rand() % 100;
        b = rand() % 100;
        f = rand() % 100;
        g = rand() % 100;
        c = rand() % 4;
        while (f == 0)
        {
         f = rand() % 100;
        }
        printf("第%d题:%d/%d / %d/%d = ",e+1, a, b, f, g);
        break;
       }
      }
     }
     system("pause");
     return 0;
    }

    总结:虽然通过运用C语言实现了这个小程序大部分要求,但是还是没有想到避免重复的方法。

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  • 原文地址:https://www.cnblogs.com/nanzhujue/p/9751865.html
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