对于每一组数据(b,a),统计b在a中出现的次数。
一道裸的KMP匹配题,你用BM我也没意见。
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1 program pku3461(input,output);
2 var
3 a,b : ansistring;
4 next : array[0..20000] of longint;
5 cases : longint;
6 i,j,k : longint;
7 answer : longint;
8 begin
9 readln(cases);
10 for k:=1 to cases do
11 begin
12 readln(b);
13 readln(a);
14 fillchar(next,sizeof(next),0);
15 j:=0;
16 next[1]:=0;
17 for i:=2 to length(b) do
18 begin
19 while (b[j+1]<>b[i])and(j>0) do
20 j:=next[j];
21 if b[j+1]=b[i] then
22 inc(j);
23 next[i]:=j;
24 end;
25 j:=0;
26 answer:=0;
27 for i:=1 to length(a) do
28 begin
29 while (j>0)and(a[i]<>b[j+1]) do
30 j:=next[j];
31 if a[i]=b[j+1] then
32 inc(j);
33 if j=length(b) then
34 begin
35 inc(answer);
36 j:=next[j];
37 end;
38 end;
39 writeln(answer);
40 end;
41 end.