杂题

[11,2,3,3,7,9,11,2,3]
list1=[]
for i in list:
    if i not in list1:
        list1.append(i)
print(list1)

lst=set(list)     # 有问题 下面是正确的
ret=lst.sort(key=list.index)
print(ret)

ret = list(set(l1))   # 正确的
print(ret)
ret.sort(key=l1.index)  # 按值在l1中的索引进行排序
print(ret)

list2=[{"name":'alex',"age":36},{"name":"god","age":26},{"name":"xiao","age":27}]
# dict={"alex":{"name":'alex',"age":36},
#        "god":{"name":"god","age":26},
#        "xiao":{"name":"xiao","age":26}}
list2.sort(key=lambda x:x["age"])
print(list2)

c=(250,200)
commd="fire:%s,%s"%c
print(commd)
commd1="fire:{}".format(c)
print(commd1)

name="alex"
age=9000
s="{} is {}".format(name,age)
print(s)
ss=f"{name} is {age}"
print(ss)

 

 def foo(arg,li=[]):

    li.append(arg)
    return li

list1=foo(21)
list2=foo(21,[1,])
list3=foo(28)

print(list1)
print(list2)
print(list3)
# [21, 28]
# [1, 21]
# [21, 28]

li=[]
def foo(arg):
    li.append(arg)
    return li

list1=foo(21)
list2=foo(21)
list3=foo(28)

print(list1)
print(list2)
print(list3)

# 结果都是[21,21,28]

# li.append()  没有返回值
def foo(arg,li=[]):
    return li.append(arg)

list1=foo(21)
list2=foo(21,[1,])
list3=foo(28)

print(list1)
print(list2)
print(list3)
# None
# None
# None


list5=[11,22,33,44,55]
print(list5[10:])
# []
---------------------------------------------------------------

list1 = [11, [22, 3], [4, ], [55, 66], 8, [9, [7, [12, [34, [26]]]]]]    ------搞不懂
# 去除多余嵌套的列表,得到[11, 22, 3, 4, 55, 66, 8]

# 小剥皮
# [11, [22, 3]]
# [11, [22, [3, 4]]
def func(x):
    return [a for b in x for a in func(b)] if isinstance(x, list) else [x]

def f(x):
    ret = []
    for b in x:
        if isinstance(b, list):
            for a in f(b):
                ret.append(a)
        else:
            ret.append(b)
    return ret

list2 = [11, 22, [33, 44], [55, [66, 77]], [88, [99, [100, [200, [300]]]]]]
ret = f(list2)
print(ret)
ret2 = func(list2)
print(ret2)

--------------------------------------------------------------

# 随机打乱列表参数顺序
import random
random.shuffle(list5)
print(list5)

相当于一个dom树的一个节点，同一个对象，不停的动态添加（类似于指针）

---------------------------------------------------------------

 #! /usr/bin/env python

# -*- coding: utf-8 -*-
# __author__ = "Q1mi"
# Date: 2017/11/24

"""
Python全栈课前练习题
"""

# s = "Alex SB 哈哈
x:1
y:2
z:3

自行车"

# # 问题1：如何取到["Alex SB 哈哈
x:1
y:2
z:3", "自行车"]?
# s1=s.split("

")
# print(s1)

# # 问题2：如何在上面结果基础上拿到["Alex", "SB", "哈哈"]?
# s1=['Alex SB 哈哈
x:1
y:2
z:3', '自行车']
# s11=s1[0].split("
")[0].split()
# print(s11)
# # 问题3：如何在上面结果基础上拿到"SB"?
# s2=["Alex", "SB", "哈哈"]
# print(s2[1])

# ------------------------------------------------------------------------------------------


# 有一个列表，他的内部是一些元祖，元祖的第一个元素是姓名，第二个元素是爱好。
# 现在我给你一个姓名，如"Egon",如果有这个姓名，就打印出他的爱好，没有就打印查无此人。

list1 = [
    ("Alex", "烫头"),
    ("Egon", "街舞"),
    ("Yuan", "喝茶")
]

for i in list1:
    if "Egon"==i[0]:
        print(i[1])
        break
else:print("查无此人")


# for i in list1:      #  有问题
#     dict={}
#     dict[i[0]]=i[1]
# print(dict)


# ------------------------------------------------------------------------------------------

# 我有一个HTML文件"login.html"

# 问题1：我如何读取它的内容保存到变量html_s？

# with open("login.html","r",encoding="utf-8") as f:
#     html_s=f.read()
# print(html_s)

# 问题2：我如何读取它的二进制内容保存到变量html_b？
# with open("login.html","rb",) as f:   #  不加 encoding
#     html_s=f.read()
# print(html_s)

------------------------------------------------------------------------------------------