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  • 第十节:子查询

    一、子查询

      1、含义

        嵌套在其他语句内部的select语句称为子查询或内查询,即一个查询的结果作为另一个查询的条件。
        外面的语句可以是insert、update、delete、select等,一般select作为外面语句较多
        外面如果为select语句,则此语句称为外查询或主查询。

      2、分类

        (1)按功能不同(结果集的行列数不同)

          ① 标量子查询(结果集只有一行一列)

            

          ② 列子查询(结果集只有一列多行)

            

          ③行子查询(结果集只有多行多列,一行多列)

          ④ 表子查询(结果集一般为多行多列)

            

        (2)按子查询出现的位置

          select 后面:

            仅仅支持标量子查询

          from 后面:

            表子查询

          where 或 having 后面:   

            标量子查询
            列子查询
            行子查询

          exists 后面:

            标量子查询
            列子查询
            行子查询
            表子查询

    二、where 或 having 后面

      1、使用子查询

        特点:
        ① 子查询放在小括号内;
        ② 子查询一般放在条件的右侧;
        ③ 标量子查询,一般搭配单行操作符使用(>,>=, <, <=, = ,<>)
        ④ 列子查询,一般搭配多行操作符使用 (IN、ANY/SOME、 ALL)
        ⑤ 子查询的执行优先于主查询执行,主查询的条件用到了子查询的结果

      2、标量子查询(单行子查询)

        (1)谁的工资比 Abel 高?

          ① 查询 Abel 的工资

    SELECT 
      salary 
    FROM
      employees 
    WHERE last_name = 'Abel' ;
    

      

          ② 查询员工的信息,salary 大于 ①

    SELECT * 
    FROM employees 
    WHERE salary > 
      (SELECT 
        salary 
      FROM
        employees 
      WHERE last_name = 'Abel'
    );
    

      

        (2)返回 job_id 与 141号员工相同,salary比 143 号员工多的员工姓名,job_id 和工资

          ① 查询141号的 job_id

    SELECT 
      job_id 
    FROM
      employees 
    WHERE employee_id = 141 ;
    

      

          ② 查询143 号工资

    SELECT 
      salary 
    FROM
      employees 
    WHERE employee_id = 143 ;
    

          ③ 查询员工的姓名,job_id 和工资,要求 job_id=① 并且 salary > ②

    SELECT *
    FROM employees
    WHERE job_id = (
    	SELECT job_id
    	FROM employees 
    	WHERE employee_id = 141
    )
    AND salary > (
    	SELECT salary
    	FROM employees
    	WHERE employee_id = 143
    );
    

      

        (3)返回公司工资最少的员工的last_name, job_id 和 salary

          ① 查询公司的最低工资

    SELECT 
      MIN(salary) 
    FROM
      employees ;
    

      

          ② 查询last_name, job_id和 salary,要求 salary = ①

    SELECT last_name, job_id, salary
    FROM employees
    WHERE salary = (
    	SELECT MIN(salary)
    	FROM employees
    );
    

      

        (4)查询最低工资大于50号部门最低工资的部门id和其最低工资

          ① 查询 50号部门的最低工资

    SELECT 
      MIN(salary) 
    FROM
      employees 
    WHERE department_id = '50' ;

          ② 查询每个部门的最低工资 

    SELECT department_id, MIN(salary)
    FROM employees
    GROUP BY department_id;

          ③ 在②上面筛选,满足 min(salry) > ① 

    SELECT department_id, MIN(salary)
    FROM employees
    GROUP BY department_id
    HAVING MIN(salary) > (
    	SELECT MIN(salary)
    	FROM employees
    	WHERE department_id = '50'
    );
    

        (5)非法使用标量子查询:子查询结果不是一行一列

    SELECT department_id, MIN(salary)
    FROM employees
    GROUP BY department_id
    HAVING MIN(salary) > (
    	SELECT salary
    	FROM employees
    	WHERE department_id = '50'
    );
    

      3、列子查询(多行子查询)

        多行子查询操作符:
        多行比较操作符:
        操作符 含义

    IN、NOT IN (不)等于列表中的任意一个
    ANY、SOME 和子查询返回的某一个值比较
    ALL 和子查询返回的所有值比较

         (1)返回location_id是1400或1700的部门中的所有员工姓名

            ① 查询 location_id 是1400或1700的部门编号

    SELECT DISTINCT 
      department_id 
    FROM
      departments 
    WHERE location_id IN (1400, 1700) ;
    

      

            ② 查询员工姓名,要求部门号是①列表中的某一个

    SELECT last_name
    FROM employees
    WHERE department_id IN (
    	SELECT DISTINCT department_id
    	FROM departments 
    	WHERE location_id IN (1400, 1700)
    );
    

            使用 ANY 实现:

    SELECT last_name
    FROM employees
    WHERE department_id = ANY (
    	SELECT DISTINCT department_id
    	FROM departments 
    	WHERE location_id IN (1400, 1700)
    );
    

      

        (2)返回其他工种中比 job_id为 'IT_PROG'工种任意工资低的员工的:工号、姓名、job_id 以及 salary

          ① 查询 job_id 为 'IT_PROG' 的工资

    SELECT DISTINCT salary
    FROM employees
    WHERE job_id = 'IT_PROG';
    

      

          ② 查询部门不是 'IT_PROG' 的部门中比①任意工资低

    SELECT employee_id, last_name, job_id, salary
    FROM employees
    WHERE job_id != 'IT_PROG'
    AND salary < ANY(
    	SELECT DISTINCT salary
    	FROM employees
    	WHERE job_id = 'IT_PROG'
    );
    

            使用 ANY 实现:

    SELECT employee_id, last_name, job_id, salary
    FROM employees
    WHERE job_id != 'IT_PROG'
    AND salary < (
    	SELECT DISTINCT MAX(salary)
    	FROM employees
    	WHERE job_id = 'IT_PROG'
    );
    

      

        (3)返回其他工种中比job_id为 'IT_PROG'工种所有工资都低的员工的员工号、姓名、job_id 以及 salary

          ① 查询工种为 'IT_PROG' 的工资 

    SELECT DISTINCT salary
    FROM employees
    WHERE job_id = 'IT_PROG';
    

      

          ② 查询工种不是 'IT_PROG' 的工种中都比①工资低

    SELECT employee_id, last_name, job_id, salary
    FROM employees
    WHERE job_id != 'IT_PROG'
    AND salary < ALL(
    	SELECT DISTINCT salary
    	FROM employees
    	WHERE job_id = 'IT_PROG'
    );
    

             方式二:

    SELECT employee_id, last_name, job_id, salary
    FROM employees
    WHERE job_id != 'IT_PROG'
    AND salary < (
    	SELECT DISTINCT MIN(salary)
    	FROM employees
    	WHERE job_id = 'IT_PROG'
    );
    

      

      4、行子查询(结果集一行多列或多行多列)

        (1)查询员工编号最小并且工资最高的员工信息

          ① 查询最小的员工编号

    SELECT MIN(employee_id)
    FROM employees;
    

      

          ② 查询最高工资

    SELECT MAX(salary)
    FROM employees;
    

      

          ③ 查询员工信息

    SELECT *
    FROM employees
    WHERE employee_id = (
    	SELECT MIN(employee_id)
    	FROM employees
    ) AND salary = (
    	SELECT MAX(salary)
    	FROM employees
    );
    

      

          ④ 方式二:

    SELECT *
    FROM employees
    WHERE (employee_id, salary) = (
    	SELECT MIN(employee_id), MAX(salary)
    	FROM employees
    );
    

      

     

    三、select 后面

      1、select 后面仅仅支持标量子查询

      2、案例

        (1)查询每个部门的员工个数

    SELECT d.*,(
    	SELECT COUNT(*) 
    	FROM employees e
    	WHERE e.department_id = d.`department_id`
    ) 个数
    FROM departments d;
    

      

        (2)查询员工号 = 102的部门号

    SELECT (
    	SELECT department_name
    	FROM departments d
    	INNER JOIN employees e
    	ON d.department_id = e.department_id
    	WHERE e.employee_id = '102'
    ) 部门名;
    

      

    四、from 后面

      1、from 后面的子查询结果充当一张表,必须要起别名

      2、案例

        (1)查询每个部门的平均工资的工资等级

          ① 查询每个部门的平均工资

    SELECT AVG(salary), department_id
    FROM employees
    GROUP BY department_id;
    

          ② 连接①的结果集合job_grades表,筛选条件平均工资

    SELECT ag_dep.*, g.grade_level
    FROM (
    	SELECT AVG(salary) ag, department_id
    	FROM employees
    	GROUP BY department_id
    ) ag_dep
    INNER JOIN job_grades g
    ON ag_dep.ag BETWEEN g.lowest_sal AND g.highest_sal;
    

      

    五、exists 后面

      1、exists 子查询

        exists 又称为相关子查询

        子查询的结果有没有值,返回布尔值。

        语法:

    exists(完整的查询语句)
    

        结果:1 或 0

      2、案例

        (1)

    SELECT EXISTS(SELECT employee_id FROM employees WHERE salary = 30000);  #0
    

      

        (2)查询有员工名的部门名

           ① 方式一

    SELECT department_name
    FROM departments d
    WHERE EXISTS(
    	SELECT *
    	FROM employees e
    	WHERE e.`department_id` = d.`department_id`
    );
    

      

           ② 方式二

    SELECT department_name
    FROM departments d
    WHERE d.`department_id` IN(
    	SELECT department_id
    	FROM employees
    );
    

      

        (3)查询没有女朋友的男生信息

          ① 方式一:in

    SELECT bo.*
    FROM boys bo
    WHERE bo.id NOT IN (
    	SELECT boyfriend_id
    	FROM beauty
    );
    

      

          ② 方式二:exists

    SELECT bo.*
    FROM boys bo
    WHERE NOT EXISTS(
    	SELECT boyfriend_id
    	FROM beauty b
    	WHERE b.`boyfriend_id` = bo.`id`
    );
    

      

    六、案例

      1、查询工资最低的员工信息: last_name, salary

        ① 查询最低的工资

    SELECT 
      MIN(salary) 
    FROM
      employees ;
    

      

        ② 查询last_name,salary,要求salary=①

    SELECT last_name,salary
    FROM employees
    WHERE salary=(
    	SELECT MIN(salary)
    	FROM employees
    );
    

      

      2、查询平均工资最低的部门信息

        方式一:

          ① 各部门的平均工资

    SELECT AVG(salary),department_id
    FROM employees
    GROUP BY department_id;
    

      

          ② 查询①结果上的最低平均工资

    SELECT MIN(ag)
    FROM (
    	SELECT AVG(salary) ag,department_id
    	FROM employees
    	GROUP BY department_id
    ) ag_dep;
    

      

          ③ 查询哪个部门的平均工资=②

    SELECT AVG(salary),department_id
    FROM employees
    GROUP BY department_id
    HAVING AVG(salary)=(
    	SELECT MIN(ag)
    	FROM (
    		SELECT AVG(salary) ag,department_id
    		FROM employees
    		GROUP BY department_id
    	) ag_dep
    
    );
    

      

          ④ 查询部门信息

    SELECT d.*
    FROM departments d
    WHERE d.`department_id`=(
    	SELECT department_id
    	FROM employees
    	GROUP BY department_id
    	HAVING AVG(salary)=(
    		SELECT MIN(ag)
    		FROM (
    			SELECT AVG(salary) ag,department_id
    			FROM employees
    			GROUP BY department_id
    		) ag_dep
    
    	)
    
    );
    

      

        方式二:

          ① 各部门的平均工资

    SELECT AVG(salary),department_id
    FROM employees
    GROUP BY department_id;
    

      

          ② 求出最低平均工资的部门编号

    SELECT department_id
    FROM employees
    GROUP BY department_id
    ORDER BY AVG(salary) 
    LIMIT 1;
    

      

          ③ 查询部门信息

    SELECT *
    FROM departments
    WHERE department_id=(
    	SELECT department_id
    	FROM employees
    	GROUP BY department_id
    	ORDER BY AVG(salary) 
    	LIMIT 1
    );
    

      

      3、查询平均工资最低的部门信息和该部门的平均工资

        ① 各部门的平均工资

    SELECT 
      AVG(salary),
      department_id 
    FROM
      employees 
    GROUP BY department_id ;
    

      

        ② 求出最低平均工资的部门编号

    SELECT 
      AVG(salary),
      department_id 
    FROM
      employees 
    GROUP BY department_id 
    ORDER BY AVG(salary) 
    LIMIT 1 ;
    

      

        ③ 查询部门信息

    SELECT d.*,ag
    FROM departments d
    JOIN (
    	SELECT AVG(salary) ag,department_id
    	FROM employees
    	GROUP BY department_id
    	ORDER BY AVG(salary) 
    	LIMIT 1
    
    ) ag_dep
    ON d.`department_id`=ag_dep.department_id;
    

      

      4、查询平均工资最高的 job 信息

        ① 查询最高的job的平均工资

    SELECT 
      AVG(salary),
      job_id 
    FROM
      employees 
    GROUP BY job_id 
    ORDER BY AVG(salary) DESC 
    LIMIT 1 ;
    

      

        ② 查询job信息

    SELECT * 
    FROM jobs
    WHERE job_id=(
    	SELECT job_id
    	FROM employees
    	GROUP BY job_id
    	ORDER BY AVG(salary) DESC
    	LIMIT 1
    
    );
    

      

      5、查询平均工资高于公司平均工资的部门有哪些?

        ① 查询平均工资

    SELECT 
      AVG(salary) 
    FROM
      employees ;
    

      

        ② 查询每个部门的平均工资

    SELECT 
      AVG(salary),
      department_id 
    FROM
      employees 
    GROUP BY department_id ;
    

      

        ③ 筛选②结果集,满足平均工资>①

    SELECT AVG(salary),department_id
    FROM employees
    GROUP BY department_id
    HAVING AVG(salary)>(
    	SELECT AVG(salary)
    	FROM employees
    
    );
    

      

      6、查询出公司中所有 manager 的详细信息

        ① 查询所有manager的员工编号

    SELECT DISTINCT 
      manager_id 
    FROM
      employees ;
    

      

        ② 查询详细信息,满足employee_id=①

    SELECT *
    FROM employees
    WHERE employee_id = ANY(
    	SELECT DISTINCT manager_id
    	FROM employees
    
    );
    

      

      7、各个部门中 最高工资中最低的那个部门的 最低工资是多少

        ① 查询各部门的最高工资中最低的部门编号

    SELECT department_id
    FROM employees
    GROUP BY department_id
    ORDER BY MAX(salary)
    LIMIT 1;
    

      

        ② 查询①结果的那个部门的最低工资

    SELECT MIN(salary) ,department_id
    FROM employees
    WHERE department_id=(
    	SELECT department_id
    	FROM employees
    	GROUP BY department_id
    	ORDER BY MAX(salary)
    	LIMIT 1
    
    
    );
    

      

      8、查询平均工资最高的部门的 manager 的详细信息: last_name, department_id, email, salary

        ① 查询平均工资最高的部门编号

    SELECT 
        department_id 
    FROM
        employees 
    GROUP BY department_id 
    ORDER BY AVG(salary) DESC 
    LIMIT 1 ;
    

      

        ② 将employees和departments连接查询,筛选条件是①

      SELECT 
            last_name, d.department_id, email, salary 
        FROM
            employees e 
            INNER JOIN departments d 
                ON d.manager_id = e.employee_id 
        WHERE d.department_id = 
            (SELECT 
                department_id 
            FROM
                employees 
            GROUP BY department_id 
            ORDER BY AVG(salary) DESC 
            LIMIT 1) ;
    

      

    七、练习

      1、查询和Zlotkey相同部门的员工姓名和工资

        ① 查询Zlotkey的部门

      SELECT 
        department_id 
      FROM
        employees 
      WHERE last_name = 'Zlotkey' ;
    

      

        ② 查询部门号=①的姓名和工资

    SELECT 
      last_name,
      salary 
    FROM
      employees 
    WHERE department_id = 
      (SELECT 
        department_id 
      FROM
        employees 
      WHERE last_name = 'Zlotkey') ;
    

      

      2、查询工资比公司平均工资高的员工的员工号,姓名和工资。

        ① 查询平均工资

    SELECT 
      AVG(salary) 
    FROM
      employees ;
    

      

        ② 查询工资>①的员工号,姓名和工资。

    SELECT 
      last_name,
      employee_id,
      salary 
    FROM
      employees 
    WHERE salary > 
      (SELECT 
        AVG(salary) 
      FROM
        employees) ;
    

      

      3、查询各部门中工资比本部门平均工资高的员工的员工号, 姓名和工资

        ① 查询各部门的平均工资

    SELECT 
      AVG(salary),
      department_id 
    FROM
      employees 
    GROUP BY department_id ;
    

      

        ② 连接①结果集和employees表,进行筛选

    SELECT 
      employee_id,
      last_name,
      salary,
      e.department_id 
    FROM
      employees e 
      INNER JOIN 
        (SELECT 
          AVG(salary) ag,
          department_id 
        FROM
          employees 
        GROUP BY department_id) ag_dep 
        ON e.department_id = ag_dep.department_id 
    WHERE salary > ag_dep.ag ;
    

      

      4、查询和姓名中包含字母u的员工在相同部门的员工的员工号和姓名

        ① 查询姓名中包含字母u的员工的部门

    SELECT DISTINCT 
      department_id 
    FROM
      employees 
    WHERE last_name LIKE '%u%' ;
    

      

        ② 查询部门号=①中的任意一个的员工号和姓名

    SELECT last_name,employee_id
    FROM employees
    WHERE department_id IN(
    	SELECT  DISTINCT department_id
    	FROM employees
    	WHERE last_name LIKE '%u%'
    );
    

      

      5、查询在部门的location_id为1700的部门工作的员工的员工号

        ① 查询location_id为1700的部门

    SELECT DISTINCT 
      department_id 
    FROM
      departments 
    WHERE location_id = 1700 ;
    

      

        ② 查询部门号=①中的任意一个的员工号

    SELECT employee_id
    FROM employees
    WHERE department_id =ANY(
    	SELECT DISTINCT department_id
    	FROM departments 
    	WHERE location_id  = 1700
    
    );
    

      

      6、查询管理者是King的员工姓名和工资

        ① 查询姓名为king的员工编号

    SELECT 
      employee_id 
    FROM
      employees 
    WHERE last_name = 'K_ing' ;
    

      

        ② 查询哪个员工的manager_id = ①

    SELECT last_name,salary
    FROM employees
    WHERE manager_id IN(
    	SELECT employee_id
    	FROM employees
    	WHERE last_name  = 'K_ing'
    
    );
    

      

      7、查询工资最高的员工的姓名,要求first_name和last_name显示为一列,列名为 姓.名

        ① 查询最高工资

    SELECT 
      MAX(salary) 
    FROM
      employees ;
    

      

        ② 查询工资=①的姓.名

    SELECT CONCAT(first_name,last_name) "姓.名"
    FROM employees
    WHERE salary=(
    	SELECT MAX(salary)
    	FROM employees
    
    );
    

      

      子查询小结:

        (1)子查询结果只要是单列,则在 where 后面作为条件;

        (2)子查询结果只要是多列,则子 from 后面作为表进行二次查询;

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  • 原文地址:https://www.cnblogs.com/niujifei/p/14886411.html
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