zoukankan      html  css  js  c++  java
  • LeetCode

    题目:

    Given an array of words and a length L, format the text such that each line has exactly L characters and is fully (left and right) justified.

    You should pack your words in a greedy approach; that is, pack as many words as you can in each line. Pad extra spaces ' ' when necessary so that each line has exactly L characters.

    Extra spaces between words should be distributed as evenly as possible. If the number of spaces on a line do not divide evenly between words, the empty slots on the left will be assigned more spaces than the slots on the right.

    For the last line of text, it should be left justified and no extra space is inserted between words.

    For example,
    words: ["This", "is", "an", "example", "of", "text", "justification."]
    L: 16.

    Return the formatted lines as:

    [
       "This    is    an",
       "example  of text",
       "justification.  "
    ]
    

    Note: Each word is guaranteed not to exceed L in length.

    思路:线性往前推

    package manipulation;
    
    import java.util.ArrayList;
    import java.util.List;
    
    public class TextJustification {
    
        public List<String> fullJustify(String[] words, int maxWidth) {
            List<String> res = new ArrayList<String>();
            int n = words.length;
            int i = 0;
            int len = 0;
            int start = 0;
            for (; i < n; ++i) {     
                if (len + words[i].length() + (i == start ? 0 : 1) > maxWidth) {
                    justify(words, start, i - 1, res, maxWidth);
                    start = i;
                    len = 0;
                }
                len += words[i].length() + (i == start ? 0 : 1);
            }
            justify(words, start, n - 1, res, maxWidth);
            return res;
        }
        
        private void justify(String[] words, int start, int end, List<String> res, int L) {
            int count = 0;
            int total = 0;
            for (int i = start; i <= end; ++i) {
                ++count;
                total += words[i].length();
            }
            int rem = L - total;
            // Only one word in this line
            if (count == 1) {
                String space = "";
                for (int i = 0; i < rem; ++i) space += " ";
                res.add(words[start] + space);
            } else if (end == words.length - 1) { // This is the last line
                String s = words[start];
                for (int i = 1; i <= count - 1; ++i) {
                    s += " " + words[start + i];
                }
                for (int i = 0; i < rem - count + 1; ++i) s+= " ";
                res.add(s);
            } else { // General case
                int avg = rem / (count - 1);
                int leftMore = rem - avg * (count  - 1);
                String s = words[start];
                for (int i = 1; i <= count - 1; ++i) {
                    for (int j = 0; j < avg; ++j) s += " ";
                    s += leftMore-- > 0 ? " " : "";
                    s += words[start + i];
                }
                res.add(s);
            }
        }
        
        public static void main(String[] args) {
            // TODO Auto-generated method stub
            String[] words = { "This", "is", "an", "example", "of", "text", "justification." };
            TextJustification t = new TextJustification();
            for (String s : t.fullJustify(words, 16)){
                System.out.println(s);
            }
        }
    
    }
  • 相关阅读:
    随机生成字符串,可用来当id
    自己总结的关于uniapp项目用androidstuido打包成apk
    css3 滑动效果 门
    在数组里面随机获取随机的几个内容
    把一个数组分割成两个(不管奇数还是偶数)
    Mysql常用命令
    怎样才能彻底地删除多余输入法软件
    启动MySQL服务
    linux监控命令全覆盖
    浅谈MVC模式与SSH框架
  • 原文地址:https://www.cnblogs.com/null00/p/5087730.html
Copyright © 2011-2022 走看看