1.问题描述
Given a string containing just the characters '(', ')', '{', '}', '[' and ']', determine if the input string is valid.The brackets must close in the correct order, "()" and "()[]{}" are all valid but "(]" and "([)]" are not.
2.解法分析
典型的栈用法。
class Solution {public:bool isValid(string s) {// Start typing your C/C++ solution below// DO NOT write int main() functionvector<char> myStack;map<char,char>dict;dict.insert(make_pair('(',')'));dict.insert(make_pair('[',']'));dict.insert(make_pair('{','}'));for(int i=0;i<s.length();++i){if(s[i]=='('||s[i]=='['||s[i]=='{')myStack.push_back(s[i]);elseif(s[i]==')'||s[i]==']'||s[i]=='}'){if(myStack.empty())return false;if(dict[myStack.back()]==s[i])myStack.pop_back();else return false;}}if(myStack.empty())return true;return false;}};