zoukankan      html  css  js  c++  java
  • POJ 1936.All in All

    All in All
    Time Limit:1000MS     Memory Limit:30000KB     64bit IO Format:%I64d & %I64u

    Description

    You have devised a new encryption technique which encodes a message by inserting between its characters randomly generated strings in a clever way. Because of pending patent issues we will not discuss in detail how the strings are generated and inserted into the original message. To validate your method, however, it is necessary to write a program that checks if the message is really encoded in the final string. 

    Given two strings s and t, you have to decide whether s is a subsequence of t, i.e. if you can remove characters from t such that the concatenation of the remaining characters is s. 

    Input

    The input contains several testcases. Each is specified by two strings s, t of alphanumeric ASCII characters separated by whitespace.The length of s and t will no more than 100000.

    Output

    For each test case output "Yes", if s is a subsequence of t,otherwise output "No".

    Sample Input

    sequence subsequence
    person compression
    VERDI vivaVittorioEmanueleReDiItalia
    caseDoesMatter CaseDoesMatter
    

    Sample Output

    Yes
    No
    Yes
    No

    应该算是水题吧~

    用两个变量记录指向s、t字符串的位置。

    如果相等,则把指向s的+1

    看循环完s是否在最后即可

    AC代码:GitHub

     1 /*
     2 By:OhYee
     3 Github:OhYee
     4 HomePage:http://www.oyohyee.com
     5 Email:oyohyee@oyohyee.com
     6 Blog:http://www.cnblogs.com/ohyee/
     7 
     8 かしこいかわいい?
     9 エリーチカ!
    10 要写出来Хорошо的代码哦~
    11 */
    12 
    13 #include <cstdio>
    14 #include <algorithm>
    15 #include <cstring>
    16 #include <cmath>
    17 #include <string>
    18 #include <iostream>
    19 #include <vector>
    20 #include <list>
    21 #include <queue>
    22 #include <stack>
    23 #include <map>
    24 using namespace std;
    25 
    26 //DEBUG MODE
    27 #define debug 0
    28 
    29 //循环
    30 #define REP(n) for(int o=0;o<n;o++)
    31 
    32 const int maxn = 100005;
    33 
    34 bool Do() {
    35     char s[maxn],t[maxn];
    36     if(scanf("%s%s",s,t) == EOF)
    37         return false;
    38     
    39     int t_len = strlen(t);
    40     int s_len = strlen(s);
    41 
    42     int it = 0;
    43     for(int i = 0;i < t_len;i++) {
    44         if(s[it] == t[i])
    45             it++;
    46         if(it == s_len)
    47             break;
    48     }
    49 
    50     printf("%s
    ",(it == s_len) ? "Yes" : "No");
    51 
    52     return true;
    53 }
    54 
    55 int main() {
    56     while(Do());
    57     return 0;
    58 }
  • 相关阅读:
    如何快速正确的安装 Ruby, Rails 运行环境
    五种开源协议的比较(BSD,Apache,GPL,LGPL,MIT) – 整理
    CocoaPods安装和使用教程
    ARC下需要注意的内存管理
    iOS 遍历某一对象的属性和方法
    使用命令行工具运行Xcode 7 UI Tests
    手势知多少
    Customizing UIWebView requests with NSURLProtocol
    iOS: JS和Native交互的两种方法
    NSURLProtocol
  • 原文地址:https://www.cnblogs.com/ohyee/p/5472303.html
Copyright © 2011-2022 走看看