不使用局部变量和for循环或其它循环打印出如m=19,n=2結果为2 4 8 16 16 8 4 2形式的串

需求：不使用局部变量和for循环或其它循环打印形如：2 4 8 16 16 8 4 2 这样的串

代码MainTest.java

package com.szp.study.javase.special;

/**
 * 正向输出n的2的倍数，当大于m时始除以2并反向除于2输出，形如m=19,n=2;結果：2 4 8 16 16 8 4 2 
 * 在方法中不声明本地变量、不使用循环
 * 
 * @author zhipengs
 * 
 */
public class MainTest {

    /**
     * @param args
     */
    public static void main(String[] args) {
        int m = 19, n = 2;
        System.out.println("m=" + m + ",n=" + n);
        m = printMulti(m, n);// 调用递归乘
        printDivide(m, n);// 调用递归除
        
        m = 35;
        n = 4;
        System.out.println("
m=" + m + ",n=" + n);
        m = printMulti(m, n);
        printDivide(m, n);
        
        m = 40;
        n = 5;
        System.out.println("
m=" + m + ",n=" + n);
        m = printMulti(m, n);
        printDivide(m, n);
        
        m = 21;
        n = 1;
        System.out.println("
m=" + m + ",n=" + n);
        m = printMulti(m, n);
        printDivide(m, n);

    }

    /**
     * 递归乘
     * @param m
     * @param n
     * @return int
     */
    public static int printMulti(int m, int n) {
        if (n <= m) {
            System.out.print(n + " ");
            n = 2 * n;
            return printMulti(m, n);
        }
        return n;
    }

    /**
     * 递归除
     * @param m
     * @param n
     * @return int
     */
    public static int printDivide(int m, int n) {
        if (m > n) {
            m = m / 2;
            System.out.print(m + " ");
            return printDivide(m, n);
        }
　　　　 return n;
    }

}

测试结果：

m=19,n=2
2 4 8 16 16 8 4 2
m=35,n=4
4 8 16 32 32 16 8 4
m=40,n=5
5 10 20 40 40 20 10 5
m=21,n=1
1 2 4 8 16 16 8 4 2 1