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  • Gray Code

    1. Title

    89. Gray Code

    2. Http address

    https://leetcode.com/problems/gray-code/?tab=Description

    3. The question

    The gray code is a binary numeral system where two successive values differ in only one bit.

    Given a non-negative integer n representing the total number of bits in the code, print the sequence of gray code. A gray code sequence must begin with 0.

    For example, given n = 2, return [0,1,3,2]. Its gray code sequence is:

    00 - 0
    01 - 1
    11 - 3
    10 - 2

    Note:
    For a given n, a gray code sequence is not uniquely defined.

    For example, [0,2,3,1] is also a valid gray code sequence according to the above definition.

    For now, the judge is able to judge based on one instance of gray code sequence. Sorry about that.

    4 My code(AC)

    public class Solution {
        public List<Integer> grayCode(int n) {
            
    
            List<Integer> reList = new ArrayList<Integer>();
            reList.add(0);
            if (n <= 0) {
                return reList;
            }
    
            int cur = 0;
            String curBinaryStr = Integer.toBinaryString(cur);
                n = 1 << n;
            curBinaryStr = "0" + curBinaryStr;
            for (int i = 1; i < n ; i++) {
                int len = curBinaryStr.length();
                for (int j = len -1; j >= 0; j--) {
                    String newStr = curBinaryStr.substring(0, j);
                    if (curBinaryStr.charAt(j) == '1') {
                        newStr += "0";
                    } else {
                        newStr += "1";
                    }
                    newStr += curBinaryStr.substring(j + 1, len);
    
                    int newInt = Integer.valueOf(newStr, 2);
    
                    if (!reList.contains(newInt)) {
                        reList.add(newInt);
                        cur = newInt;
                        curBinaryStr = Integer.toBinaryString(cur);
                        curBinaryStr = "0" + curBinaryStr;
                        
                        break;
                    }
                }
            }
    
            return reList;
        
        }
    }
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  • 原文地址:https://www.cnblogs.com/ordili/p/6432612.html
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