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     1 #include <iostream>
     2 #include <algorithm>
     3 #include <cstring>
     4 #include <cstdio>
     5 #include <string>
     6 #include <map>
     7 #include <cmath>
     8 #include <vector>
     9 
    10 #define Faster ios::sync_with_stdio(false),cin.tie(0)
    11 #define Read freopen("in.txt","r",stdin),freopen("out.txt","w",stdout)
    12 #define Close fclose(stdin),fclose(stdout)
    13 const int maxn = 105;
    14 using namespace std;
    15 const int MOD = 1e9+7;
    16 typedef long long ll;
    17 
    18 char s1[maxn];
    19 char s2[maxn];
    20 int dp[maxn][maxn];
    21 int len;
    22 int ans[maxn];
    23 
    24 int main(){
    25     Faster;
    26     while(~scanf("%s%s", s1, s2)){
    27         len = strlen(s1);
    28         memset(dp, 0, sizeof(dp));
    29         for(int j = 0;j < len; j++){    //j为尾
    30             for(int i = j;i >= 0;i--){        //i为头
    31                 dp[i][j] = dp[i+1][j] + 1;    //每个都单独刷一次
    32                 for(int k = i+1;k <= j;k++){
    33                     if(s2[i] == s2[k]){
    34                         dp[i][j] = min(dp[i][j], (dp[i+1][k]+dp[k+1][j]));
    35                     }
    36                 }
    37             }
    38         }
    39         for(int i = 0;i < len;i++){
    40             ans[i] = dp[0][i];
    41         }
    42         for(int i = 0;i < len;i++){
    43             if(s1[i] == s2[i]){
    44                 ans[i] = ans[i-1];    //对应位置相等的话,就不用刷新
    45             }
    46             else{
    47                 for(int j = 0;j < i;j++){
    48                     ans[i] = min(ans[i], ans[j] + dp[j+1][i]);    //寻找j来分割区间的最优解
    49                 }
    50             }
    51         }
    52         printf("%d
    ", ans[len-1]);
    53     }
    54     return 0;
    55 }
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  • 原文地址:https://www.cnblogs.com/ouyang_wsgwz/p/9310932.html
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