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  • [学习笔记]树链剖分

    开始复习(NOIP)啦!

    树链剖分是一种非常实用的算法,树的重链最多只有(logn)条,所以它的复杂度是(O(nlogn))

    如果树再套上一个线段树,那么复杂度多乘一个(logn)

    那么线段树怎么表示区间呢?可以用(dfs)序修改,多开一个(id[i])表示(i)节点在线段树的位置

    我们记录一个节点的深度(dep[i]),链首数组(top[i]),重儿子(son[i]),父亲(fa[i]),一个子树的大小(siz[i])

    然后就可以愉快的解决掉【模板】树链剖分

    (Code Below:)

    #include <bits/stdc++.h>
    #define ll long long
    using namespace std;
    const ll maxn=100000+10;
    ll n,m,r,p;
    ll sum[maxn<<2],lazy[maxn<<2],a[maxn];
    ll head[maxn],from[maxn<<1],to[maxn<<1],tot;
    ll top[maxn],id[maxn],dep[maxn],son[maxn],siz[maxn],mp[maxn],fa[maxn],tim;
    
    void add(ll x,ll y){
    	to[++tot]=y;
    	from[tot]=head[x];
    	head[x]=tot;
    }
    void pushup(ll rt){sum[rt]=(sum[rt<<1]+sum[rt<<1|1])%p;}
    void pushdown(ll rt,ll len){
    	if(lazy[rt]){
    		sum[rt<<1]=(sum[rt<<1]+lazy[rt]*(len-(len>>1)))%p;
    		sum[rt<<1|1]=(sum[rt<<1|1]+lazy[rt]*(len>>1))%p;
    		lazy[rt<<1]=(lazy[rt<<1]+lazy[rt])%p;
    		lazy[rt<<1|1]=(lazy[rt<<1|1]+lazy[rt])%p;
    		lazy[rt]=0;
    	}
    }
    void build(ll l,ll r,ll rt){
    	if(l==r){
    		sum[rt]=mp[l]%p;
    		return;
    	}
    	ll mid=(l+r)>>1;
    	build(l,mid,rt<<1);
    	build(mid+1,r,rt<<1|1);
    	pushup(rt);
    }
    void update(ll L,ll R,ll C,ll l,ll r,ll rt){
    	if(L<=l&&r<=R){
    		sum[rt]=(sum[rt]+(r-l+1)*C)%p;
    		lazy[rt]=(lazy[rt]+C)%p;
    		return;
    	}
    	ll mid=(l+r)>>1;
    	pushdown(rt,r-l+1);
    	if(L<=mid) update(L,R,C,l,mid,rt<<1);
    	if(R>mid) update(L,R,C,mid+1,r,rt<<1|1);
    	pushup(rt);
    }
    ll query(ll L,ll R,ll l,ll r,ll rt){
    	if(L<=l&&r<=R) return sum[rt];
    	ll mid=(l+r)>>1,ans=0;
    	pushdown(rt,r-l+1);
    	if(L<=mid) ans=(ans+query(L,R,l,mid,rt<<1))%p;
    	if(R>mid) ans=(ans+query(L,R,mid+1,r,rt<<1|1))%p;
    	return ans;
    	
    }
    void dfs1(ll x,ll f,ll deep){
    	dep[x]=deep;
    	fa[x]=f;
    	siz[x]=1;
    	ll maxson=-1;
    	for(ll i=head[x];i;i=from[i]){
    		ll y=to[i];
    		if(y==f) continue;
    		dfs1(y,x,deep+1);
    		siz[x]+=siz[y];
    		if(siz[y]>maxson){
    			son[x]=y;
    			maxson=siz[y];
    		}
    	}
    }
    void dfs2(ll x,ll f){
    	id[x]=++tim;
    	top[x]=f;
    	mp[tim]=a[x];
    	if(son[x]) dfs2(son[x],f);
    	for(ll i=head[x];i;i=from[i]){
    		ll y=to[i];
    		if(y==fa[x]||y==son[x]) continue;
    		dfs2(y,y);
    	}
    }
    
    int main()
    {
    	scanf("%lld%lld%lld%lld",&n,&m,&r,&p);
    	for(ll i=1;i<=n;i++)
    		scanf("%lld",&a[i]);
    	for(ll i=1;i<n;i++){
    		ll x,y;
    		scanf("%lld%lld",&x,&y);
    		add(x,y);add(y,x);
    	}
    	dfs1(r,0,1);
    	dfs2(r,r);
    	build(1,n,1);
    	for(ll i=1;i<=m;i++){
    		ll op,x,y,z;
    		scanf("%lld",&op);
    		if(op==1){
    			scanf("%lld%lld%lld",&x,&y,&z);
    			while(top[x]!=top[y]){
    				if(dep[top[x]]<dep[top[y]]) swap(x,y);
    				update(id[top[x]],id[x],z,1,n,1);
    				x=fa[top[x]];
    			}
    			if(dep[x]>dep[y]) swap(x,y);
    			update(id[x],id[y],z,1,n,1);
    		}
    		if(op==2){
    			scanf("%lld%lld",&x,&y);
    			ll ans=0;
    			while(top[x]!=top[y]){
    				if(dep[top[x]]<dep[top[y]]) swap(x,y);
    				ans=(ans+query(id[top[x]],id[x],1,n,1))%p;
    				x=fa[top[x]];
    			}
    			if(dep[x]>dep[y]) swap(x,y);
    			ans=(ans+query(id[x],id[y],1,n,1))%p;
    			printf("%lld
    ",ans%p);
    		}
    		if(op==3){
    			scanf("%lld%lld",&x,&z);
    			update(id[x],id[x]+siz[x]-1,z,1,n,1);
    		}
    		if(op==4){
    			scanf("%lld",&x);
    			printf("%lld
    ",query(id[x],id[x]+siz[x]-1,1,n,1)%p);
    		}
    	}
    	return 0;
    }
    

    [ZJOI2008]树的统计

    其实就是开两个线段树,一个维护最大值,一个维护权值和,一道考验码力的题

    (Code Below:)

    #include <bits/stdc++.h>
    #define ll long long
    using namespace std;
    const ll maxn=100000+10;
    const ll inf=-100000;
    ll n,m;
    ll sum[maxn<<2],sumv[maxn<<2],lazy[maxn<<2],lazyv[maxn<<2],a[maxn];
    ll head[maxn],to[maxn<<1],nxt[maxn<<1],tot;
    ll dep[maxn],top[maxn],son[maxn],siz[maxn],fa[maxn],id[maxn],mp[maxn],tim;
    
    void add(ll x,ll y){
    	to[++tot]=y;
    	nxt[tot]=head[x];
    	head[x]=tot;
    }
    void dfs1(ll x,ll f,ll deep){
    	dep[x]=deep;
    	fa[x]=f;
    	siz[x]=1;
    	int maxson=-1;
    	for(ll i=head[x];i;i=nxt[i]){
    		ll y=to[i];
    		if(y==f) continue;
    		dfs1(y,x,deep+1);
    		siz[x]+=siz[y];
    		if(siz[y]>maxson){
    			son[x]=y;
    			maxson=siz[y];
    		}
    	}
    }
    void dfs2(ll x,ll f){
    	id[x]=++tim;
    	mp[tim]=a[x];
    	top[x]=f;
    	if(son[x]) dfs2(son[x],f);
    	for(ll i=head[x];i;i=nxt[i]){
    		ll y=to[i];
    		if(y==fa[x]||y==son[x]) continue;
    		dfs2(y,y);
    	}
    }
    void pushup(ll rt){
    	sum[rt]=sum[rt<<1]+sum[rt<<1|1];
    	sumv[rt]=max(sumv[rt<<1],sumv[rt<<1|1]);
    }
    void pushdown(ll rt,ll len){
    	if(lazy[rt]){
    		lazy[rt<<1]+=lazy[rt];
    		lazy[rt<<1|1]+=lazy[rt];
    		sum[rt<<1]+=lazy[rt]*(len-(len>>1));
    		sum[rt<<1|1]+=lazy[rt]*(len>>1);
    		lazy[rt]=0;
    	}
    	if(lazyv[rt]){
    		lazyv[rt<<1]=lazyv[rt];
    		lazyv[rt<<1|1]=lazyv[rt];
    		sumv[rt]=lazyv[rt];
    		sumv[rt]=lazyv[rt];
    		lazyv[rt]=0;
    	}
    }
    void build(ll l,ll r,ll rt){
    	if(l==r){
    		sum[rt]=sumv[rt]=mp[l];
    		return;
    	}
    	ll mid=(l+r)>>1;
    	build(l,mid,rt<<1);
    	build(mid+1,r,rt<<1|1);
    	pushup(rt);
    }
    void update(ll L,ll C,ll l,ll r,ll rt){
    	if(l==L&&r==L){
    		sum[rt]=sumv[rt]=C;
    		lazy[rt]+=C;lazyv[rt]=C;
    		return;
    	}
    	ll mid=(l+r)>>1;
    	pushdown(rt,r-l+1);
    	if(L<=mid) update(L,C,l,mid,rt<<1);
    	if(L>mid) update(L,C,mid+1,r,rt<<1|1);
    	pushup(rt);
    }
    ll queryM(ll L,ll R,ll l,ll r,ll rt){
    	if(L<=l&&r<=R) return sumv[rt];
    	ll mid=(l+r)>>1,ans=inf;
    	pushdown(rt,r-l+1);
    	if(L<=mid) ans=max(ans,queryM(L,R,l,mid,rt<<1));
    	if(R>mid)  ans=max(ans,queryM(L,R,mid+1,r,rt<<1|1));
    	return ans;
    }
    ll queryS(ll L,ll R,ll l,ll r,ll rt){
    	if(L<=l&&r<=R) return sum[rt];
    	ll mid=(l+r)>>1,ans=0;
    	pushdown(rt,r-l+1);
    	if(L<=mid) ans+=queryS(L,R,l,mid,rt<<1);
    	if(R>mid)  ans+=queryS(L,R,mid+1,r,rt<<1|1);
    	return ans;
    }
    int main()
    {
    	scanf("%lld",&n);
    	for(ll i=1;i<n;i++){
    		ll x,y;
    		scanf("%lld%lld",&x,&y);
    		add(x,y);add(y,x);
    	}
    	for(ll i=1;i<=n;i++)
    		scanf("%lld",&a[i]);
    	scanf("%lld",&m);
    	dfs1(1,0,1);
    	dfs2(1,1);
    	build(1,n,1);
    	for(ll i=1;i<=m;i++){
    		char op[10];ll x,y;
    		scanf("%s%lld%lld",&op,&x,&y);
    		if(op[0]=='C'){
    			update(id[x],y,1,n,1);
    		}
    		else if(op[0]=='Q'&&op[1]=='M'){
    			ll ans=inf;
    			while(top[x]!=top[y]){
    				if(dep[top[x]]<dep[top[y]]) swap(x,y);
    				ans=max(ans,queryM(id[top[x]],id[x],1,n,1));
    				x=fa[top[x]];
    			}
    			if(dep[x]>dep[y]) swap(x,y);
    			ans=max(ans,queryM(id[x],id[y],1,n,1));
    			printf("%lld
    ",ans);
    		}
    		else {
    			ll ans=0;
    			while(top[x]!=top[y]){
    				if(dep[top[x]]<dep[top[y]]) swap(x,y);
    				ans+=queryS(id[top[x]],id[x],1,n,1);
    				x=fa[top[x]];
    			}
    			if(dep[x]>dep[y]) swap(x,y);
    			ans+=queryS(id[x],id[y],1,n,1);
    			printf("%lld
    ",ans);
    		}
    	}
    	return 0;	
    }
    

    [HAOI2015]树上操作

    太特殊了吧,直接暴力都行啊

    但是上树剖更快(qwq)

    (Code Below:)

    // luogu-judger-enable-o2
    #pragma GCC optimize(2)
    #include <bits/stdc++.h>
    #define ll long long
    using namespace std;
    const ll maxn=100000+10;
    ll n,m,r,p;
    ll sum[maxn<<2],lazy[maxn<<2],a[maxn];
    ll head[maxn],from[maxn<<1],to[maxn<<1],tot;
    ll top[maxn],id[maxn],dep[maxn],son[maxn],siz[maxn],mp[maxn],fa[maxn],tim;
    
    void add(ll x,ll y){
    	to[++tot]=y;
    	from[tot]=head[x];
    	head[x]=tot;
    }
    void pushup(ll rt){sum[rt]=(sum[rt<<1]+sum[rt<<1|1])%p;}
    void pushdown(ll rt,ll len){
    	if(lazy[rt]){
    		sum[rt<<1]=(sum[rt<<1]+lazy[rt]*(len-(len>>1)))%p;
    		sum[rt<<1|1]=(sum[rt<<1|1]+lazy[rt]*(len>>1))%p;
    		lazy[rt<<1]=(lazy[rt<<1]+lazy[rt])%p;
    		lazy[rt<<1|1]=(lazy[rt<<1|1]+lazy[rt])%p;
    		lazy[rt]=0;
    	}
    }
    void build(ll l,ll r,ll rt){
    	if(l==r){
    		sum[rt]=mp[l]%p;
    		return;
    	}
    	ll mid=(l+r)>>1;
    	build(l,mid,rt<<1);
    	build(mid+1,r,rt<<1|1);
    	pushup(rt);
    }
    void update(ll L,ll R,ll C,ll l,ll r,ll rt){
    	if(L<=l&&r<=R){
    		sum[rt]=(sum[rt]+(r-l+1)*C)%p;
    		lazy[rt]=(lazy[rt]+C)%p;
    		return;
    	}
    	ll mid=(l+r)>>1;
    	pushdown(rt,r-l+1);
    	if(L<=mid) update(L,R,C,l,mid,rt<<1);
    	if(R>mid) update(L,R,C,mid+1,r,rt<<1|1);
    	pushup(rt);
    }
    ll query(ll L,ll R,ll l,ll r,ll rt){
    	if(L<=l&&r<=R) return sum[rt];
    	ll mid=(l+r)>>1,ans=0;
    	pushdown(rt,r-l+1);
    	if(L<=mid) ans=(ans+query(L,R,l,mid,rt<<1))%p;
    	if(R>mid) ans=(ans+query(L,R,mid+1,r,rt<<1|1))%p;
    	return ans;
    	
    }
    void dfs1(ll x,ll f,ll deep){
    	dep[x]=deep;
    	fa[x]=f;
    	siz[x]=1;
    	ll maxson=-1;
    	for(ll i=head[x];i;i=from[i]){
    		ll y=to[i];
    		if(y==f) continue;
    		dfs1(y,x,deep+1);
    		siz[x]+=siz[y];
    		if(siz[y]>maxson){
    			son[x]=y;
    			maxson=siz[y];
    		}
    	}
    }
    void dfs2(ll x,ll f){
    	id[x]=++tim;
    	top[x]=f;
    	mp[tim]=a[x];
    	if(son[x]) dfs2(son[x],f);
    	for(ll i=head[x];i;i=from[i]){
    		ll y=to[i];
    		if(y==fa[x]||y==son[x]) continue;
    		dfs2(y,y);
    	}
    }
    
    int main()
    {
    	scanf("%lld%lld",&n,&m);r=1;p=1e15;
    	for(ll i=1;i<=n;i++)
    		scanf("%lld",&a[i]);
    	for(ll i=1;i<n;i++){
    		ll x,y;
    		scanf("%lld%lld",&x,&y);
    		add(x,y);add(y,x);
    	}
    	dfs1(r,0,1);
    	dfs2(r,r);
    	build(1,n,1);
    	for(ll i=1;i<=m;i++){
    		ll op,x,y,z;
    		scanf("%lld",&op);
    		if(op==1){
    			scanf("%lld%lld",&x,&z);
    			y=x;
    			while(top[x]!=top[y]){
    				if(dep[top[x]]<dep[top[y]]) swap(x,y);
    				update(id[top[x]],id[x],z,1,n,1);
    				x=fa[top[x]];
    			}
    			if(dep[x]>dep[y]) swap(x,y);
    			update(id[x],id[y],z,1,n,1);
    		}
    		if(op==2){
    			scanf("%lld%lld",&x,&z);
    			update(id[x],id[x]+siz[x]-1,z,1,n,1);
    		}
    		if(op==3){
    			scanf("%lld",&x);
    			ll ans=0;y=1;
    			while(top[x]!=top[y]){
    				if(dep[top[x]]<dep[top[y]]) swap(x,y);
    				ans=(ans+query(id[top[x]],id[x],1,n,1))%p;
    				x=fa[top[x]];
    			}
    			if(dep[x]>dep[y]) swap(x,y);
    			ans=(ans+query(id[x],id[y],1,n,1))%p;
    			printf("%lld
    ",ans);
    		}
    	}
    	return 0;
    }
    

    [NOI2015]软件包管理器

    解释操作:

    1、安装操作:先查询(i)节点到根节点的和,将(i)节点到根节点的值从(0)改成(1)

    2、卸载操作:先查询(i)节点子树的和,再修改(i)节点子树的值从(1)改成(0)

    那么直接上裸的树剖就好吧

    (Code Below:)

    #include <bits/stdc++.h>
    #define ll long long
    using namespace std;
    const ll maxn=100000+10;
    ll n,m,r,p;
    ll sum[maxn<<2],lazy[maxn<<2],a[maxn];
    ll head[maxn],from[maxn<<1],to[maxn<<1],tot;
    ll top[maxn],id[maxn],dep[maxn],son[maxn],siz[maxn],mp[maxn],fa[maxn],tim;
    
    void add(ll x,ll y){
        to[++tot]=y;
        from[tot]=head[x];
        head[x]=tot;
    }
    void pushup(ll rt){sum[rt]=(sum[rt<<1]+sum[rt<<1|1])%p;}
    void pushdown(ll rt,ll len){
        if(lazy[rt]!=-1){
            sum[rt<<1]=lazy[rt]*(len-(len>>1))%p;
            sum[rt<<1|1]=lazy[rt]*(len>>1)%p;
            lazy[rt<<1]=lazy[rt]%p;
            lazy[rt<<1|1]=lazy[rt]%p;
            lazy[rt]=-1;
        }
    }
    void build(ll l,ll r,ll rt){
        if(l==r){
            sum[rt]=mp[l]%p;
            return;
        }
        ll mid=(l+r)>>1;
        build(l,mid,rt<<1);
        build(mid+1,r,rt<<1|1);
        pushup(rt);
    }
    void update(ll L,ll R,ll C,ll l,ll r,ll rt){
        if(L<=l&&r<=R){
            sum[rt]=(r-l+1)*C%p;
            lazy[rt]=C%p;
            return;
        }
        ll mid=(l+r)>>1;
        pushdown(rt,r-l+1);
        if(L<=mid) update(L,R,C,l,mid,rt<<1);
        if(R>mid) update(L,R,C,mid+1,r,rt<<1|1);
        pushup(rt);
    }
    ll query(ll L,ll R,ll l,ll r,ll rt){
        if(L<=l&&r<=R) return sum[rt];
        ll mid=(l+r)>>1,ans=0;
        pushdown(rt,r-l+1);
        if(L<=mid) ans=(ans+query(L,R,l,mid,rt<<1))%p;
        if(R>mid) ans=(ans+query(L,R,mid+1,r,rt<<1|1))%p;
        return ans;
        
    }
    void dfs1(ll x,ll f,ll deep){
        dep[x]=deep;
        fa[x]=f;
        siz[x]=1;
        ll maxson=-1;
        for(ll i=head[x];i;i=from[i]){
            ll y=to[i];
            if(y==f) continue;
            dfs1(y,x,deep+1);
            siz[x]+=siz[y];
            if(siz[y]>maxson){
                son[x]=y;
                maxson=siz[y];
            }
        }
    }
    void dfs2(ll x,ll f){
        id[x]=++tim;
        top[x]=f;
        mp[tim]=a[x];
        if(son[x]) dfs2(son[x],f);
        for(ll i=head[x];i;i=from[i]){
            ll y=to[i];
            if(y==fa[x]||y==son[x]) continue;
            dfs2(y,y);
        }
    }
    
    int main()
    {
        memset(lazy,-1,sizeof(lazy));
        scanf("%lld",&n);r=1;p=1e15;
        for(ll i=1;i<n;i++){
            ll x,y;
            scanf("%lld",&x);
            add(x+1,i+1);add(i+1,x+1);
        }
        dfs1(r,0,1);
        dfs2(r,r);
        build(1,n,1);
        scanf("%lld",&m);
        for(ll i=1;i<=m;i++){
            char op[20];ll x,y,z;
            scanf("%s",op);
            if(op[0]=='i'){
                scanf("%lld",&x);y=1;z=1;
                ll Ans=0;x++;ll nx=x;
                while(top[x]!=top[y]){
                    if(dep[top[x]]<dep[top[y]]) swap(x,y);
                    Ans=(Ans+query(id[top[x]],id[x],1,n,1))%p;
                    x=fa[top[x]];
                }
                if(dep[x]>dep[y]) swap(x,y);
                Ans=(Ans+query(id[x],id[y],1,n,1))%p;
                x=nx;y=1;
                while(top[x]!=top[y]){
                    if(dep[top[x]]<dep[top[y]]) swap(x,y);
                    update(id[top[x]],id[x],z,1,n,1);
                    x=fa[top[x]];
                }
                if(dep[x]>dep[y]) swap(x,y);
                update(id[x],id[y],z,1,n,1);
                ll ans=dep[nx];
                printf("%lld
    ",ans-Ans);
            }
            else {
                scanf("%lld",&x);z=0;x++;
                printf("%lld
    ",query(id[x],id[x]+siz[x]-1,1,n,1)%p);
                update(id[x],id[x]+siz[x]-1,z,1,n,1);
            }
        }
        return 0;
    }
    

    [SHOI2012]魔法树

    其实就是软件包管理器的加强版

    (Code Below:)

    #include <bits/stdc++.h>
    #define ll long long
    #define res register int
    #define mid (l+r>>1)
    using namespace std;
    const int maxn=100000+10;
    int n,q,head[maxn],to[maxn<<1],nxt[maxn<<1],tot;
    ll sum[maxn<<2],lazy[maxn<<2];
    int top[maxn],son[maxn],dep[maxn],fa[maxn],id[maxn],siz[maxn],tim;
    
    inline int read(){
    	res x=0,f=1;char ch=getchar();
    	while(ch<'0'||ch>'9'){if(ch=='-')f=-1;ch=getchar();}
    	while(ch>='0'&&ch<='9'){x=(x<<3)+(x<<1)+ch-'0';ch=getchar();}
    	return (f==1)?x:-x;
    }
    void print(int x){
    	if(x<0){putchar('-');x=-x;}
    	if(x>=10) print(x/10);
    	putchar(x%10+'0');
    }
    inline void swap(int &a,int &b){res t=a;a=b;b=t;}
    inline void pushup(int rt){sum[rt]=sum[rt<<1]+sum[rt<<1|1];}
    inline void pushdown(int rt,int len){
    	if(lazy[rt]){
    		sum[rt<<1]+=lazy[rt]*(len-(len>>1));
    		sum[rt<<1|1]+=lazy[rt]*(len>>1);
    		lazy[rt<<1]+=lazy[rt];
    		lazy[rt<<1|1]+=lazy[rt];
    		lazy[rt]=0;
    	}
    }
    void update(int L,int R,int C,int l,int r,int rt){
    	if(L <= l && r <= R){
    		sum[rt]+=(r-l+1)*C;
    		lazy[rt]+=C;
    		return ;
    	}
    	pushdown(rt,r-l+1);
    	if(L <= mid) update(L,R,C,l,mid,rt<<1);
    	if(R > mid) update(L,R,C,mid+1,r,rt<<1|1);
    	pushup(rt);
    }
    ll query(int L,int R,int l,int r,int rt)
    {
    	if(L <= l && r <= R){
    		return sum[rt];
    	}
    	ll ans=0;
    	pushdown(rt,r-l+1);
    	if(L <= mid) ans+=query(L,R,l,mid,rt<<1);
    	if(R > mid) ans+=query(L,R,mid+1,r,rt<<1|1);
    	return ans;
    }
    inline void add(int x,int y){
    	to[++tot]=y;
    	nxt[tot]=head[x];
    	head[x]=tot;
    }
    void dfs1(int x,int f){
    	dep[x]=dep[f]+1;
    	siz[x]=1;
    	fa[x]=f;
    	ll maxson=-1;
    	for(res i=head[x];i;i=nxt[i]){
    		res y=to[i];
    		if(y==f) continue;
    		dfs1(y,x);
    		siz[x]+=siz[y];
    		if(maxson<siz[y]){
    			son[x]=y;
    			maxson=siz[y];
    		}
    	}
    }
    void dfs2(int x,int topf){
    	id[x]=++tim;
    	top[x]=topf;
    	if(son[x]) dfs2(son[x],topf);
    	for(res i=head[x];i;i=nxt[i]){
    		res y=to[i];
    		if(y==fa[x]||y==son[x]) continue;
    		dfs2(y,y);
    	}
    }
    
    int main()
    {
    	n=read();
    	res x,y;
    	for(res i=1;i<n;i++){
    		x=read(),y=read();
    		add(x+1,y+1);add(y+1,x+1);
    	}
    	dfs1(1,1);
    	dfs2(1,1);
    	q=read();
    	char ch;res u,v,d;
    	while(q--){
    		ch=getchar();
    		while(ch!='A'&&ch!='Q') ch=getchar();
    		if(ch=='A'){
    			u=read()+1,v=read()+1,d=read();
    			for(;top[u]!=top[v];){
    				if(dep[top[u]]<dep[top[v]]) swap(u,v);
    				update(id[top[u]],id[u],d,1,n,1);
    				u=fa[top[u]];
    			}
    			if(dep[u]>dep[v]) swap(u,v);
    			update(id[u],id[v],d,1,n,1); 
    		}
    		else {
    			u=read()+1;
    			printf("%lld
    ",query(id[u],id[u]+siz[u]-1,1,n,1));
    		}
    	}
    	return 0;
    }
    
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  • 原文地址:https://www.cnblogs.com/owencodeisking/p/9584278.html
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