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  • HashMap扩容-jdk1.9

    1. threshold HashMap扩容阈值
        capacity(容量) * loadFactor(加载因子),如果new对象没有传入容量,则阈值大小为0,如果传入容量,则通过tableSizeFor 设置为大于容量的最小的2的幂次。

    2. 扩容源码

     1 final Node<K,V>[] resize() {
     2         Node<K,V>[] oldTab = table;
     3         int oldCap = (oldTab == null) ? 0 : oldTab.length;
     4         int oldThr = threshold;
     5         int newCap, newThr = 0;
     6         //table 不为空
     7         if (oldCap > 0) {
     8             //无法扩容
     9             if (oldCap >= MAXIMUM_CAPACITY) {
    10                 threshold = Integer.MAX_VALUE;
    11                 return oldTab;
    12             }//扩容2倍
    13             else if ((newCap = oldCap << 1) < MAXIMUM_CAPACITY &&
    14                      oldCap >= DEFAULT_INITIAL_CAPACITY)
    15                 newThr = oldThr << 1; // double threshold
    16         }
    17         //以下table 为空情况
    18         else if (oldThr > 0) //table 为空情况且 设置了初始大小initial capacity,新容量为阈值大小
    19             newCap = oldThr;
    20         else {               //table 为空情况且没有设置初始容量,采用默认值初始化
    21             newCap = DEFAULT_INITIAL_CAPACITY;
    22             newThr = (int)(DEFAULT_LOAD_FACTOR * DEFAULT_INITIAL_CAPACITY);
    23         }
    24         if (newThr == 0) {  //阈值
    25             float ft = (float)newCap * loadFactor;
    26             newThr = (newCap < MAXIMUM_CAPACITY && ft < (float)MAXIMUM_CAPACITY ?
    27                       (int)ft : Integer.MAX_VALUE);
    28         }
    29         threshold = newThr;
    30         @SuppressWarnings({"rawtypes","unchecked"})
    31             Node<K,V>[] newTab = (Node<K,V>[])new Node[newCap];
    32         table = newTab;
    33         if (oldTab != null) {
    34             for (int j = 0; j < oldCap; ++j) {
    35                 Node<K,V> e;
    36                 if ((e = oldTab[j]) != null) {
    37                     oldTab[j] = null;
    38                     //只有一个节点,直接放入新table中
    39                     if (e.next == null)
    40                         newTab[e.hash & (newCap - 1)] = e;
    41                     //为红黑树,则对树进行拆分
    42                     else if (e instanceof TreeNode)
    43                         ((TreeNode<K,V>)e).split(this, newTab, j, oldCap);
    44                     //链表拆分,原链表拆分成2个链表newTab[j],newTab[j + oldCap]为2个链表的头结点
    45                     else { // preserve order
    46                         Node<K,V> loHead = null, loTail = null;
    47                         Node<K,V> hiHead = null, hiTail = null;
    48                         Node<K,V> next;
    49                         do {
    50                             next = e.next;
    51                             if ((e.hash & oldCap) == 0) {
    52                                 if (loTail == null)
    53                                     loHead = e;
    54                                 else
    55                                     loTail.next = e;
    56                                 loTail = e;
    57                             }
    58                             else {
    59                                 if (hiTail == null)
    60                                     hiHead = e;
    61                                 else
    62                                     hiTail.next = e;
    63                                 hiTail = e;
    64                             }
    65                         } while ((e = next) != null);
    66                         if (loTail != null) {
    67                             loTail.next = null;
    68                             newTab[j] = loHead;
    69                         }
    70                         if (hiTail != null) {
    71                             hiTail.next = null;
    72                             newTab[j + oldCap] = hiHead;
    73                         }
    74                     }
    75                 }
    76             }
    77         }
    78         return newTab;
    79     }

    3.  由于扩容是比较耗性能的操作,所以一开始就尽量预测好初始容量,以减少扩容带来的性能损耗,比如 HashMap(1000),考虑变更为 new HashMap(1024) 但是不是最佳,因为加载因子默认0.75,即 

    0.75*1000<1000,阈值小于1000,故最好设置为new HashMap(2048),就能避免resize

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  • 原文地址:https://www.cnblogs.com/oxf5deb3/p/13472815.html
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