zoukankan      html  css  js  c++  java
  • URAL 1297 Palindrome(Manacher)

    The “U.S. Robots” HQ has just received a rather alarming anonymous letter. It states that the agent from the competing «Robots Unlimited» has infiltrated into “U.S. Robotics”. «U.S. Robots» security service would have already started an undercover operation to establish the agent’s identity, but, fortunately, the letter describes communication channel the agent uses. He will publish articles containing stolen data to the “Solaris” almanac. Obviously, he will obfuscate the data, so “Robots Unlimited” will have to use a special descrambler (“Robots Unlimited” part number NPRx8086, specifications are kept secret).
    Having read the letter, the “U.S. Robots” president recalled having hired the “Robots Unlimited” ex-employee John Pupkin. President knows he can trust John, because John is still angry at being mistreated by “Robots Unlimited”. Unfortunately, he was fired just before his team has finished work on the NPRx8086 design.
    So, the president has assigned the task of agent’s message interception to John. At first, John felt rather embarrassed, because revealing the hidden message isn’t any easier than finding a needle in a haystack. However, after he struggled the problem for a while, he remembered that the design of NPRx8086 was still incomplete. “Robots Unlimited” fired John when he was working on a specific module, the text direction detector. Nobody else could finish that module, so the descrambler will choose the text scanning direction at random. To ensure the correct descrambling of the message by NPRx8086, agent must encode the information in such a way that the resulting secret message reads the same both forwards and backwards.
    In addition, it is reasonable to assume that the agent will be sending a very long message, so John has simply to find the longest message satisfying the mentioned property.
    Your task is to help John Pupkin by writing a program to find the secret message in the text of a given article. As NPRx8086 ignores white spaces and punctuation marks, John will remove them from the text before feeding it into the program.

    Input

    The input consists of a single line, which contains a string of Latin alphabet letters (no other characters will appear in the string). String length will not exceed 1000 characters.

    Output

    The longest substring with mentioned property. If there are several such strings you should output the first of them.
     
    题目大意:求最长回文子串并输出。
    思路:Manacher算法的模板题,不多说。
     
    代码(0.015S):
     1 #include <cstdio>
     2 #include <algorithm>
     3 #include <cstring>
     4 #include <iostream>
     5 using namespace std;
     6 typedef long long LL;
     7 
     8 const int MAXN = 2 * 1010;
     9 
    10 char str[MAXN], s[MAXN];
    11 int n, p[MAXN];
    12 
    13 void manacher() {
    14     int mx = 0, id;
    15     for(int i = 1; i < n; ++i) {
    16         if(mx > i) p[i] = min(p[2 * id - i], mx - i);
    17         else p[i] = 1;
    18         while(s[i + p[i]] == s[i - p[i]]) ++p[i];
    19         if(i + p[i] > mx) {
    20             id = i;
    21             mx = i + p[i];
    22         }
    23     }
    24 }
    25 
    26 void print() {
    27     int id = 0;
    28     for(int i = 1; i < n; ++i)
    29         if(p[i] > p[id]) id = i;
    30     int l = (id - p[id] + 1) / 2, r = l + p[id] - 1;
    31     for(int i = l; i < r; ++i) putchar(str[i]);
    32     puts("");
    33 }
    34 
    35 int main() {
    36     scanf("%s", str);
    37     s[n++] = '$', s[n++] = '#';
    38     for(int i = 0; str[i]; ++i) {
    39         s[n++] = str[i];
    40         s[n++] = '#';
    41     }
    42     s[n] = 0;
    43     manacher();
    44     print();
    45 }
    View Code
  • 相关阅读:
    CentOS 5.5如何通过yum安装Zend Optimizer
    如何更改商品分类名称的长度?
    ECSHOP的后台路径修改
    SVN协同开发时服务端与线上APACHE测试环境网站同步记录 转
    一个简单的替换字符的SQL命令
    svn 的常见操作 import
    SVN制作补丁包的方法
    kloxo密码解决办法
    SVN的分支/标记/合并
    如何将一个表中的所有字母都变成小写
  • 原文地址:https://www.cnblogs.com/oyking/p/3536396.html
Copyright © 2011-2022 走看看