5ResponseModel响应模型

使用返回值模型

class UserIn(BaseModel):
    username: str
    password: str
    email: EmailStr
    mobile: str = "10086"
    address: str = None
    full_name: Optional[str] = None


class UserOut(BaseModel):
    username: str
    email: EmailStr  # 用 EmailStr 需要 pip install pydantic[email]
    mobile: str = "10086"
    address: str = None
    full_name: Optional[str] = None


users = {
    "user01": {"username": "user01", "password": "123123", "email": "user01@example.com"},
    "user02": {"username": "user02", "password": "123456", "email": "user02@example.com", "mobile": "110"}
}


@app04.post("/response_model/", response_model=UserOut, response_model_exclude_unset=True)
async def response_model(user: UserIn):
    """
    response_model_exclude_unset=True  表示默认值不包含在响应中，仅包含实际给的值，如果实际给的值与默认值相同也会包含在响应中
    response_model: 使用哪个返回模型
    """
    print(user.password)  # password不会被返回
    # return user
    return users["user01"]

返回模型参数参数的使用

@app04.post(
    "/response_model/attributes",
    response_model=UserOut,
    # response_model=Union[UserIn, UserOut],    # 使用两个模型类的并集
    # response_model=List[UserOut],             # 列表里面的任意一个响应模型类都可以
    response_model_include=["username", "email", "mobile"],
    response_model_exclude=["mobile"]
)
async def response_model_attributes(user: UserIn):
    """
    response_model_include列出需要在返回结果中包含的字段；
    response_model_exclude列出需要在返回结果中排除的字段
    """
    # del user.password  # Union[UserIn, UserOut]后，删除password属性也能返回成功
    return user
    # return [user, user]

响应状态吗

@app04.post("/status_code", status_code=200)
async def status_code():
    return {"status_code": 200}


@app04.post("/status_attribute", status_code=status.HTTP_200_OK)
async def status_attribute():
    print(type(status.HTTP_200_OK))
    return {"status_code": status.HTTP_200_OK}