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    《算法竞赛入门经典-训练指南》P198
    记录一下区间的左右边界就可以了
    #include <iostream>
    #include <stack>
    #include <queue>
    #include <cstdio>
    #include <cstdlib>
    #include <cmath>
    #include <set>
    #include <vector>
    #include <cstring>
    #include <algorithm>
    
    #define INF 0x7fffffff
    #define N 100010
    #define M 1000010
    #define LL long long
    #define mod 95041567
    
    using namespace std;
    
    int arr[N];
    int num[N][3];
    int dp[N][20];
    
    void RMQ_init(int len){
        for(int j = 1; (1 << j) <= len; ++ j)
            for(int i = 1; i + (1 << j) - 1 < len; ++ i)
                dp[i][j] = max(dp[i][j - 1], dp[i + (1 << (j - 1))][j - 1]);
    }
    
    int RMQ(int L, int R){
        if(R < L) return 0;
        else if(R == L) return dp[R][0];
        int k = 0;
        while((1 << (k + 1)) <= R - L + 1) ++ k;
        return max(dp[L][k], dp[R - (1 << k) + 1][k]);
    }
    
    int main()
    {
        int n, q;
       // freopen("in.txt","r",stdin);
        while(scanf("%d", &n) != EOF){
            if(! n) break;
            scanf("%d", &q);
            for(int i = 0; i < n; ++ i) scanf("%d", &arr[i]);
            for(int i = 0; i <= n + 2; ++ i)
                for(int j = 0; j <= 20; ++ j)
                    dp[i][j] = 0;
            arr[n] = INF;
            int p = 0;
            int len = 0;
            for(int i = 1; i <= n; ++ i)
                if(arr[i] != arr[i - 1]){
                    for(int j = p; j <= i - 1; ++ j){
                        num[j][0] = i - 1;
                        num[j][1] = p;
                        num[j][2] = len;
                    }
                    dp[len ++][0] = i - p;
                    p = i;
                }
            RMQ_init(len);
            int L, R;
            for(int i = 0; i < q; ++ i){
                scanf("%d %d", &L, &R);
                if(arr[L - 1] == arr[R - 1]){
                    printf("%d
    ", R - L + 1);
                    continue;
                }
                //printf("%s
    ", "++");
                p = num[L - 1][0] - (L - 1) + 1;
                p = max(p, R - num[R - 1][1]);
                p = max(p, RMQ(num[L - 1][2] + 1, num[R - 1][2] - 1));
                printf("%d
    ", p);
            }
        }
        return 0;
    }


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  • 原文地址:https://www.cnblogs.com/pangblog/p/3367758.html
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