19. Remove Nth Node From End of List

题目：

Given a linked list, remove the nth node from the end of list and return its head.

For example,

   Given linked list: 1->2->3->4->5, and n = 2.

   After removing the second node from the end, the linked list becomes 1->2->3->5.

Note:
Given n will always be valid.
Try to do this in one pass.

链接：https://leetcode.com/problems/remove-nth-node-from-end-of-list/#/description

4/11/2017

87%, 14ms

要了解每个变量的意义，想不出来就画图，不要猜初始值定在哪里
fast也可以设在dummy上，这样第8，12行就按照fast.next来判断，不过运行时间会加到18ms

public class Solution {
    public ListNode removeNthFromEnd(ListNode head, int n) {
        if (head == null || n <= 0) return head;
        ListNode dummy = new ListNode(-1);
        dummy.next = head;
        ListNode fast = head;
        ListNode slow = dummy;
        while (n > 0 && fast != null) {
            fast = fast.next;
            n--;
        }
        while (fast != null) {
            fast = fast.next;
            slow = slow.next;
        }
        slow.next = slow.next.next;
        return dummy.next;
    }
}

官方解答

https://leetcode.com/articles/remove-nth-node-end-list/