//重建数据库 101, create database testdatabase;use database testdatabase; 102, create table tt1(id int, name varchar(20),age int,sex boolean); 103, show tables;desc tt1; //插入 104, insert into tt1 values(1,"zhang",25,0); 105, insert into tt1 values(2,"wang",25,1); 106, select * from tt1; 107, insert into tt1(id,name,age,sex) values(3,"li",28,1); 108, insert into tt1(id,name,sex,age) values(4,"sun",0,22); 109, insert into tt1(id,name,sex) values(5,"zhao",30,1); 110, insert into tt1(id,age,name) values(6,"he",47,0); 111, insert into tt1(id,age,name) values(7,"chen",22,1),(7,"zhang",22,1),(7,"xie",32,1); 112, select * from tt1; //修改 113, update tt1 set id=10,name="new",age=100,sex=0 where id=1; select * from tt1; 114, update tt1 set id=11,name="new" where id=2,age=25; select *from tt1; 115, updatett1 set id=12,sex=1 where id=7; select * from tt1; 116, update tt1 set sex=1 where id>3; 117, updatett1 set sex=0 where id<4; //删除 118, delete from tt1 where id=1;select * from tt1; 119, delete fromtt1 where id=12;select * from tt1; //查询 120, alter table tt1 add address varchar(30); 121, update tt1 set address="Beijing" where sex=1; 122, update tt1 set address="Shanghai" where sex=0; //简单查询 123, select id from tt1; 124, select id,name from tt1; 125, select id,name,address from tt1; //条件查询 126, select id,name,address from tt1 where address="Beijing"; 127, select * from tt1 where id in(2,3,4); 128, select * from tt1 where id not in(2,3,4); 129, select * from tt1 where id between 2 and 5; 130, select * from tt1 where id not between 2 and 5; 131, select * from tt1 where address like "beijing"; 132, select * from tt1 where address like "bei"; 133, select * from tt1 where address like "bei%"; 134, select * from tt1 where address not like "bei%"; 135, select * from tt1 where address is null; 136, select * from tt1 where address is not null; 137, select * from tt1 where age<20 and sex=1;138, select * from tt1 where sex=0 or age>30; //查询结果不重复 139, select distinct address from tt1;//查询结果排序 140, select * from tt1 order by age; 141, select * from tt1 order by age asc; 142, select * from tt1 order by age desc; //分组查询 143, select * from tt1 group by sex;//单独使用group by 只会选择每个分组的一条记录 //group by 与 group_concat结合使用 144, select group_concat(name),sex from tt1 group by sex; 145, select group_concat(name),group_concat(age),sex from tt1 group by sex; 146, select group_concat(name,age),sex from tt1 group by sex; //group by与集合函数结合使用 147, select sex,count(sex) from tt1 group by sex; 148, select sex,count(sex) from tt1 group by sex having sex>2;//having用于对分组后的结果加限制条件 149, select sex,count(sex) from tt1 group by sex having count(sex)>2; //with rollup 150, select sex,count(sex) from tt1 group by sex with rollup;//在显示记录的最后一行加一条，记录是上面所有记录的和，通常用于合计数量 //limit显示限制 151, select * from tt1; 152, select * from tt1 limit2; 153, select * from tt1 limit 3; 154, select * from tt1 limit 0,2; 155, select * from tt1 limit 1,2; //使用集合函数查询 //为了更好的理解本问题，新建一个表 156, create table grade(id int,name varchar(10),subject varchar(10),score int,sex boolean); 157, insert into grade values(1,"wang","math",100,1),(1,"wang","english",96,1),(1,"wang","physics",90,1); insert into grade values(2,"li","math",96,1),(2,"li","english",85,1),(2,"li","physics",99,1); insert into grade values(3,"sun","math",85,0),(3,"sun","english",98,0),(3,"sun","physics",80,0); 158, select * from grade; 159, select count(*) from grade; 160, select id,name,sum(score) from grade where id=1; 161, select id,name,sun(score) from grade group by id; 162, select id,name,sum(score) from grade group by id order by sum(score) desc; 163, select id,name,avg(score) from grade where id=2; 164, select id,name,avg(score),sum(score) from grade where id =3; 165, select id,name,avg(score) from grade group by id; 166, select subject,avg(score) from grade group by subject;* from 167, select subject,avg(score) from grade group by subject order by avg(score); 168, select name,max(score) from grade where subject="math"; 169, select name,max(score) from grade where subject="english"; //连接查询 //内连接 170, create table stu(id int,name varchar(10),ageint,sex boolean); 171, insert into stu values(1,"wang",25,1),(2,"li",23,1),(3,"sun",23,0),(4,"zhou",27,1),(5,"zhang",22,0); 172, select id,name,age,sex,score from stu,grade where stu.id=grade.id; 173, select stu.id,stu.name,stu.age,stu.sex,score from stu,grade where stu.id=grade.id; 174, select stu.id,stu.name,stu.age,stu.sex,score from stu,grade where stu.id=grade.id and score>90; //外连接 175, select stu.id,stu.name,stu.age,stu.sex,score from stu left join grade on stu.id=grade.id; 176, select stu.id,stu.name,stu.age,stu,sex,score from stu right join grade on stu.id=grade.id; 177, insert into grade values(4,"hu","math",99,1),(5,"liu","english",97,0); 178, select stu.id,stu.name,stu.age,stu.sex,subject,score from stu left join grade on stu.id=grade.id; 179, select stu.id,stu.name,stu.age,stu.sex,subject,score from stu right join grade on stu.id=grade.id; //子查询 180, select * from stu where idin (select *from grade); 181, select * from grade where id in (select * from stu); 182, create tablescholarship(level int,money int,score int); 183, insert into scholarship values(1,10000,90),(2,5000,85),(3,3000,80); 184, select id,name,score from grade where score>=(select score from scholarship where level=1); 185, select id,name,score from grade where score>=(select min(score) from scholarship);//exists子查询 186, select * from stu where exists (select name from grade where id=1); 187, select *from grade where score>any(select score from scholarship); 188, select * from grade where score>all(select score from scholarship); //合并查询结果 189, select name from stu union select name from grade;190, select name from stu union all select name from grade; //别名 191, select * from scholarship s where s.level=1; 192, select * from scholarship s where s.money=5000; 193, select s.name from stu s,grade g where s.name=g.name; 194, select subject as su,score as sc from grade; 195, select * from stu where name regexp "^w"; 196, select * from stu where name regexp "g$"; 197, select * from stu where name regexp "^w.g$"; 198, select * from stu where name regexp "^w..g$"; 199, select * from stu where name regexp "[aeo]"; 200, select * from stu where name regexp "[a-g]";
代码
//重建数据库 101, create database testdatabase;use database testdatabase; 102, create table tt1(id int, name varchar(20),age int,sex boolean); 103, show tables;desc tt1; //插入 104, insert into tt1 values(1,"zhang",25,0); 105, insert into tt1 values(2,"wang",25,1); 106, select * from tt1; 107, insert into tt1(id,name,age,sex) values(3,"li",28,1); 108, insert into tt1(id,name,sex,age) values(4,"sun",0,22); 109, insert into tt1(id,name,sex) values(5,"zhao",30,1); 110, insert into tt1(id,age,name) values(6,"he",47,0); 111, insert into tt1(id,age,name) values(7,"chen",22,1),(7,"zhang",22,1),(7,"xie",32,1); 112, select * from tt1; //修改 113, update tt1 set id=10,name="new",age=100,sex=0 where id=1; select * from tt1; 114, update tt1 set id=11,name="new" where id=2,age=25; select *from tt1; 115, updatett1 set id=12,sex=1 where id=7; select * from tt1; 116, update tt1 set sex=1 where id>3; 117, updatett1 set sex=0 where id<4; //删除 118, delete from tt1 where id=1;select * from tt1; 119, delete fromtt1 where id=12;select * from tt1; //查询 120, alter table tt1 add address varchar(30); 121, update tt1 set address="Beijing" where sex=1; 122, update tt1 set address="Shanghai" where sex=0; //简单查询 123, select id from tt1; 124, select id,name from tt1; 125, select id,name,address from tt1; //条件查询 126, select id,name,address from tt1 where address="Beijing"; 127, select * from tt1 where id in(2,3,4); 128, select * from tt1 where id not in(2,3,4); 129, select * from tt1 where id between 2 and 5; 130, select * from tt1 where id not between 2 and 5; 131, select * from tt1 where address like "beijing"; 132, select * from tt1 where address like "bei"; 133, select * from tt1 where address like "bei%"; 134, select * from tt1 where address not like "bei%"; 135, select * from tt1 where address is null; 136, select * from tt1 where address is not null; 137, select * from tt1 where age<20 and sex=1;138, select * from tt1 where sex=0 or age>30; //查询结果不重复 139, select distinct address from tt1;//查询结果排序 140, select * from tt1 order by age; 141, select * from tt1 order by age asc; 142, select * from tt1 order by age desc; //分组查询 143, select * from tt1 group by sex;//单独使用group by 只会选择每个分组的一条记录 //group by 与 group_concat结合使用 144, select group_concat(name),sex from tt1 group by sex; 145, select group_concat(name),group_concat(age),sex from tt1 group by sex; 146, select group_concat(name,age),sex from tt1 group by sex; //group by与集合函数结合使用 147, select sex,count(sex) from tt1 group by sex; 148, select sex,count(sex) from tt1 group by sex having sex>2;//having用于对分组后的结果加限制条件 149, select sex,count(sex) from tt1 group by sex having count(sex)>2; //with rollup 150, select sex,count(sex) from tt1 group by sex with rollup;//在显示记录的最后一行加一条，记录是上面所有记录的和，通常用于合计数量 //limit显示限制 151, select * from tt1; 152, select * from tt1 limit2; 153, select * from tt1 limit 3; 154, select * from tt1 limit 0,2; 155, select * from tt1 limit 1,2; //使用集合函数查询 //为了更好的理解本问题，新建一个表 156, create table grade(id int,name varchar(10),subject varchar(10),score int,sex boolean); 157, insert into grade values(1,"wang","math",100,1),(1,"wang","english",96,1),(1,"wang","physics",90,1); insert into grade values(2,"li","math",96,1),(2,"li","english",85,1),(2,"li","physics",99,1); insert into grade values(3,"sun","math",85,0),(3,"sun","english",98,0),(3,"sun","physics",80,0); 158, select * from grade; 159, select count(*) from grade; 160, select id,name,sum(score) from grade where id=1; 161, select id,name,sun(score) from grade group by id; 162, select id,name,sum(score) from grade group by id order by sum(score) desc; 163, select id,name,avg(score) from grade where id=2; 164, select id,name,avg(score),sum(score) from grade where id =3; 165, select id,name,avg(score) from grade group by id; 166, select subject,avg(score) from grade group by subject;* from 167, select subject,avg(score) from grade group by subject order by avg(score); 168, select name,max(score) from grade where subject="math"; 169, select name,max(score) from grade where subject="english"; //连接查询 //内连接 170, create table stu(id int,name varchar(10),ageint,sex boolean); 171, insert into stu values(1,"wang",25,1),(2,"li",23,1),(3,"sun",23,0),(4,"zhou",27,1),(5,"zhang",22,0); 172, select id,name,age,sex,score from stu,grade where stu.id=grade.id; 173, select stu.id,stu.name,stu.age,stu.sex,score from stu,grade where stu.id=grade.id; 174, select stu.id,stu.name,stu.age,stu.sex,score from stu,grade where stu.id=grade.id and score>90; //外连接 175, select stu.id,stu.name,stu.age,stu.sex,score from stu left join grade on stu.id=grade.id; 176, select stu.id,stu.name,stu.age,stu,sex,score from stu right join grade on stu.id=grade.id; 177, insert into grade values(4,"hu","math",99,1),(5,"liu","english",97,0); 178, select stu.id,stu.name,stu.age,stu.sex,subject,score from stu left join grade on stu.id=grade.id; 179, select stu.id,stu.name,stu.age,stu.sex,subject,score from stu right join grade on stu.id=grade.id; //子查询 180, select * from stu where idin (select *from grade); 181, select * from grade where id in (select * from stu); 182, create tablescholarship(level int,money int,score int); 183, insert into scholarship values(1,10000,90),(2,5000,85),(3,3000,80); 184, select id,name,score from grade where score>=(select score from scholarship where level=1); 185, select id,name,score from grade where score>=(select min(score) from scholarship);//exists子查询 186, select * from stu where exists (select name from grade where id=1); 187, select *from grade where score>any(select score from scholarship); 188, select * from grade where score>all(select score from scholarship); //合并查询结果 189, select name from stu union select name from grade;190, select name from stu union all select name from grade; //别名 191, select * from scholarship s where s.level=1; 192, select * from scholarship s where s.money=5000; 193, select s.name from stu s,grade g where s.name=g.name; 194, select subject as su,score as sc from grade; 195, select * from stu where name regexp "^w"; 196, select * from stu where name regexp "g$"; 197, select * from stu where name regexp "^w.g$"; 198, select * from stu where name regexp "^w..g$"; 199, select * from stu where name regexp "[aeo]"; 200, select * from stu where name regexp "[a-g]";