jackson将json数组转成List、普通数组。

package com.mkyong;

import com.fasterxml.jackson.core.type.TypeReference;
import com.fasterxml.jackson.databind.ObjectMapper;

import java.io.IOException;
import java.util.Arrays;
import java.util.List;

public class JacksonArrayExample {

    public static void main(String[] args) {

        ObjectMapper mapper = new ObjectMapper();
        String json = "[{"name":"mkyong", "age":37}, {"name":"fong", "age":38}]";

        try {

            // 1. convert JSON array to Array objects
            Person[] pp1 = mapper.readValue(json, Person[].class);

            System.out.println("JSON array to Array objects...");
            for (Person person : pp1) {
                System.out.println(person);
            }

            // 2. convert JSON array to List of objects
            List<Person> ppl2 = Arrays.asList(mapper.readValue(json, Person[].class));

            System.out.println("
JSON array to List of objects");
            ppl2.stream().forEach(x -> System.out.println(x));

            // 3. alternative
            List<Person> pp3 = mapper.readValue(json, new TypeReference<List<Person>>() {});

            System.out.println("
Alternative...");
            pp3.stream().forEach(x -> System.out.println(x));

        } catch (IOException e) {
            e.printStackTrace();
        }

    }
}

import lombok.Data;
import lombok.ToString;

@Data
@ToString
public class Person {
    private String name;
    private Integer age;
}

maven依赖

<dependency>
        <groupId>com.fasterxml.jackson.core</groupId>
        <artifactId>jackson-databind</artifactId>
        <version>2.9.8</version>
    </dependency>

当你的返回数据类型复杂的时候，可以用TypeReference轻松指定返回类型。

输出：

 转载自：https://www.mkyong.com/java/jackson-convert-json-array-string-to-list/

其他参考：https://www.cnblogs.com/dupang/p/5673097.html