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  • SQLAlchemy 几种查询方式总结

    转自:http://blog.csdn.net/shudaqi2010/article/details/51568219

    几种常见sqlalchemy查询:
    #简单查询    
    print(session.query(User).all())
    print(session.query(User.name, User.fullname).all())    
    print(session.query(User, User.name).all())        


    #带条件查询    
    print(session.query(User).filter_by(name='user1').all())    
    print(session.query(User).filter(User.name == "user").all())    
    print(session.query(User).filter(User.name.like("user%")).all())      

      
    #多条件查询    
    print(session.query(User).filter(and_(User.name.like("user%"), User.fullname.like("first%"))).all())    
    print(session.query(User).filter(or_(User.name.like("user%"), User.password != None)).all())        


    #sql过滤    
    print(session.query(User).filter("id>:id").params(id=1).all())        


    #关联查询     
    print(session.query(User, Address).filter(User.id == Address.user_id).all())    
    print(session.query(User).join(User.addresses).all())    
    print(session.query(User).outerjoin(User.addresses).all())        


    #聚合查询    
    print(session.query(User.name, func.count('*').label("user_count")).group_by(User.name).all())    
    print(session.query(User.name, func.sum(User.id).label("user_id_sum")).group_by(User.name).all())        


    #子查询    
    stmt = session.query(Address.user_id, func.count('*').label("address_count")).group_by(Address.user_id).subquery()    
    print(session.query(User, stmt.c.address_count).outerjoin((stmt, User.id == stmt.c.user_id)).order_by(User.id).all())     

       
    #exists    
    print(session.query(User).filter(exists().where(Address.user_id == User.id)))    
    print(session.query(User).filter(User.addresses.any()))


    限制返回字段查询
    person = session.query(Person.name, Person.created_at,Person.updated_at).filter_by(name="zhongwei").order_by(Person.created_at).first()


    记录总数查询:
    from sqlalchemy import func


    # count User records, without
    # using a subquery.
    session.query(func.count(User.id))


    # return count of user "id" grouped
    # by "name"
    session.query(func.count(User.id)).
            group_by(User.name)


    from sqlalchemy import distinct
    # count distinct "name" values
    session.query(func.count(distinct(User.name)))

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  • 原文地址:https://www.cnblogs.com/passion-hzhang/p/6036315.html
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