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  • LeetCode 175. Combine Two Tables

    https://leetcode.com/problems/combine-two-tables/description/

    Table: Person

    +-------------+---------+
    | Column Name | Type    |
    +-------------+---------+
    | PersonId    | int     |
    | FirstName   | varchar |
    | LastName    | varchar |
    +-------------+---------+
    PersonId is the primary key column for this table.
    

    Table: Address

    +-------------+---------+
    | Column Name | Type    |
    +-------------+---------+
    | AddressId   | int     |
    | PersonId    | int     |
    | City        | varchar |
    | State       | varchar |
    +-------------+---------+
    AddressId is the primary key column for this table.
    

    Write a SQL query for a report that provides the following information for each person in the Person table, regardless if there is an address for each of those people:

    FirstName, LastName, City, State

    
    
    • Since the PersonId in table Address is the foreign key of table Person, we can join this two table to get the address information of a person. 

    • Considering there might not be an address information for every person, we should use outer join instead of the default inner join.

    • Note: Using where clause to filter the records will fail if there is no address information for a person because it will not display the name information.

     1 Create table If Not Exists Person (PersonId int, FirstName varchar(255), LastName varchar(255));
     2 Create table If Not Exists Address (AddressId int, PersonId int, City varchar(255), State varchar(255));
     3 Truncate table Person;
     4 insert into Person (PersonId, LastName, FirstName) values ('1', 'Wang', 'Allen');
     5 Truncate table Address;
     6 insert into Address (AddressId, PersonId, City, State) values ('1', '2', 'New York City', 'New York');
     7 
     8 # Write your MySQL query statement below
     9 select P.FirstName, P.LastName, A.City, A.State 
    10 from Person P left join Address A 
    11 on P.PersonId = A.PersonId;
    View Code
     
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  • 原文地址:https://www.cnblogs.com/pegasus923/p/7652884.html
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