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  • SQL GROUP BY 语句:语法及案例解析

    SQL GROUP BY 语句


    GROUP BY 语句可结合一些聚合函数来使用


    GROUP BY 语句

    GROUP BY 语句用于结合聚合函数,根据一个或多个列对结果集进行分组。

    SQL GROUP BY 语法

    SELECT column_name, aggregate_function(column_name)
    FROM table_name
    WHERE column_name operator value
    GROUP BY column_name;

    演示数据库

    在本教程中,我们将使用 样本数据库。

    下面是选自 "Websites" 表的数据:

    +----+--------------+---------------------------+-------+---------+
    | id | name         | url                       | alexa | country |
    +----+--------------+---------------------------+-------+---------+
    | 1  | Google       | https://www.google.cm/    | 1     | USA     |
    | 2  | 淘宝          | https://www.taobao.com/   | 13    | CN      |
    | 3  | 菜鸟教程      | http://www.runoob.com/    | 4689  | CN      |
    | 4  | 微博          | http://weibo.com/         | 20    | CN      |
    | 5  | Facebook     | https://www.facebook.com/ | 3     | USA     |
    | 7  | stackoverflow | http://stackoverflow.com/ |   0 | IND     |
    +----+---------------+---------------------------+-------+---------+
    

    下面是 "access_log" 网站访问记录表的数据:

    mysql> SELECT * FROM access_log;
    +-----+---------+-------+------------+
    | aid | site_id | count | date       |
    +-----+---------+-------+------------+
    |   1 |       1 |    45 | 2016-05-10 |
    |   2 |       3 |   100 | 2016-05-13 |
    |   3 |       1 |   230 | 2016-05-14 |
    |   4 |       2 |    10 | 2016-05-14 |
    |   5 |       5 |   205 | 2016-05-14 |
    |   6 |       4 |    13 | 2016-05-15 |
    |   7 |       3 |   220 | 2016-05-15 |
    |   8 |       5 |   545 | 2016-05-16 |
    |   9 |       3 |   201 | 2016-05-17 |
    +-----+---------+-------+------------+
    9 rows in set (0.00 sec)
    

    GROUP BY 简单应用

    统计 access_log 各个 site_id 的访问量:

    实例

    SELECT site_id, SUM(access_log.count) AS nums
    FROM access_log GROUP BY site_id;

    执行以上 SQL 输出结果如下:


    SQL GROUP BY 多表连接

    下面的 SQL 语句统计有记录的网站的记录数量:

    实例

    SELECT Websites.name,COUNT(access_log.aid) AS nums FROM access_log
    LEFT JOIN Websites
    ON access_log.site_id=Websites.id
    GROUP BY Websites.name;

    执行以上 SQL 输出结果如下:

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  • 原文地址:https://www.cnblogs.com/peijz/p/12515366.html
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