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  • C#算法小程序(1)

    两个数组a1,a2,找到a1中第一次出现a2的元素下表:

    class Program
        {
            static void Main(string[] args)
            {
                int[] a1 = { 4, 3, 7, 6, 9, 5, 7, 6, 4 };
                int[] a2 = { 7, 6 };
    
                int result = GetFirst(a1, a2);
                Console.WriteLine(result);
                Console.ReadKey();
            }
    
            private static int GetFirst(int[] a1, int[] a2)
            {
                int first = -1;
                int a1length = a1.Length;
                int a2length = a2.Length;
                bool tag = true;
                for (int i = 0; i < a1length; i++)
                {
                    if (a1[i] == a2[0])
                    {
                        for (int j = 1; j < a2length; j++)
                        {
                            if (a2[j] != a1[i + j])
                            {
                                tag = false;
                            }
                        }
                        if (tag == true)
                        {
                            first = i;
                            break;
                        }
                    }
                }
                return first;
            }
        }
    }
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  • 原文地址:https://www.cnblogs.com/pengdotnet/p/2970985.html
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