Given an index k, return the kth row of the Pascal's triangle.
For example, given k = 3,
Return [1,3,3,1]
.
Note:
Could you optimize your algorithm to use only O(k) extra space?
下标标错了,改一次通过,总体上是水题,不过也许有空间使用更少的算法。
class Solution { public: vector<int> getRow(int rowIndex) { vector <int>vec; vec.push_back(1); for(int i = 0 ; i < rowIndex ; i++)vec.push_back(1); if(rowIndex == 1) return vec; for(int i = 1; i <=rowIndex ; i++) { vector<int> ve = vec; for(int j = 1; j < i ; j++)vec[j] = ve[j-1]+ve[j]; } return vec; } };