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  • MySQL的YEARWEEK函数(转)

    MySQL的YEARWEEK函数以及查询本周数据
    2013-03-10 16:45:10     我来说两句       作者:kamuikyo
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    MySQL的YEARWEEK函数以及查询本周数据
    MySQL 的 YEARWEEK 是获取年份和周数的一个函数,函数形式为 YEARWEEK(date[,mode]) 
    例如 2010-3-14 ,礼拜天    www.2cto.com   SELECT YEARWEEK('2010-3-14') 返回 11  SELECT YEARWEEK('2010-3-14',1) 返回 10 
    其中第二个参数是 mode ,具体指的意思如下:  www.2cto.com  
     
    Mode
    First day of week
    Range
    Week 1 is the first week …
    0
    Sunday
    0-53
    with a Sunday in this year
    1
    Monday
    0-53
    with more than 3 days this year
    2
    Sunday
    1-53
    with a Sunday in this year
    3
    Monday
    1-53
    with more than 3 days this year
    4
    Sunday
    0-53
    with more than 3 days this year
    5
    Monday
    0-53
    with a Monday in this year
    6
    Sunday
    1-53
    with more than 3 days this year
    7
    Monday
    1-53
    with a Monday in this year
     
     
     
    查询当前这周的数据 
    SELECT name,submittime FROM enterprise WHERE YEARWEEK(date_format(submittime,'%Y-%m-%d')) = YEARWEEK(now());
     
    查询上周的数据
    SELECT name,submittime FROM enterprise WHERE YEARWEEK(date_format(submittime,'%Y-%m-%d')) = YEARWEEK(now())-1;
     
     
    查询当前月份的数据
    select name,submittime from enterprise  where date_format(submittime,'%Y-%m')=date_format(now(),'%Y-%m')
     
    查询距离当前现在6个月的数据
    select name,submittime from enterprise where submittime between date_sub(now(),interval 6 month) and now();
     
    查询上个月的数据
    select name,submittime from enterprise where date_format(submittime,'%Y-%m')=date_format(DATE_SUB(curdate(), INTERVAL 1 MONTH),'%Y-%m');
    select * from `user` where DATE_FORMAT(pudate,'%Y%m') = DATE_FORMAT(CURDATE(),'%Y%m') ;
    select * from user where WEEKOFYEAR(FROM_UNIXTIME(pudate,'%y-%m-%d')) = WEEKOFYEAR(now());
    select * from user where MONTH(FROM_UNIXTIME(pudate,'%y-%m-%d')) = MONTH(now());
    select * from [user] where YEAR(FROM_UNIXTIME(pudate,'%y-%m-%d')) = YEAR(now()) and MONTH(FROM_UNIXTIME(pudate,'%y-%m-%d')) = MONTH(now());
    select * from [user] where pudate between 上月最后一天 and 下月第一天;
     
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  • 原文地址:https://www.cnblogs.com/pepperok/p/3626108.html
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