力扣（LeetCode）试题12-整数转罗马数字 C++代码

这道题写的，思路清奇？代码太臃肿了

也算是有一丢丢特点，拿出来分享一下

class Solution {
public:
    string intToRoman(int num)
    {
        stack<char> temp;
        int count = 0;
        while (num)
        {
            ++count;
            int r = num % 10;
            num /= 10;
            if (count == 1)
            {
                if (r <= 3)
                {
                    int k = r;
                    while (k--) temp.push('I');
                }
                if (r == 4)
                {
                    temp.push('V');
                    temp.push('I');
                }
                if (r == 5) temp.push('V');
                if (r>5 && r <= 8)
                {
                    int res = r - 5;
                    while (res--)
                    {
                        temp.push('I');
                    }
                    temp.push('V');
                }
                if (r == 9)
                {
                    temp.push('X');
                    temp.push('I');
                }
            }
            if (count == 2)
            {
                if (r <= 3)
                {
                    int k = r;
                    while (k--) temp.push('X');
                }
                if (r == 4)
                {
                    temp.push('L');
                    temp.push('X');
                }
                if (r == 5) temp.push('L');
                if (r>5 && r <= 8)
                {
                    int res = r-5;
                    while (res--)
                    {
                        temp.push('X');
                    }
                    temp.push('L');
                }
                if (r == 9)
                {
                    temp.push('C');
                    temp.push('X');
                }
            }
            if (count == 3)
            {
                if (r <= 3)
                {
                    int k = r;
                    while (k--) temp.push('C');
                }
                if (r == 4)
                {
                    temp.push('D');
                    temp.push('C');
                }
                if (r == 5) temp.push('D');
                if (r>5 && r <= 8)
                {
                    int res = r - 5;
                    while (res--)
                    {
                        temp.push('C');
                    }
                    temp.push('D');
                }
                if (r == 9)
                {
                    temp.push('M');
                    temp.push('C');
                }
            }
            if (count == 4)
            {
                int k = r;
                while (k--) temp.push('M');
            }
        }
        string str = "";
        while (!temp.empty())
        {
            str += temp.top();
            temp.pop();
        }
        return str;
    }
};