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  • bzoj1211

    prufer码水题
    (n-2)!/[(d1-1)!*(d2-1)!*…*(dn-1)!]

     1 var c:array[0..200] of longint;
     2     x,n,i,j,s:longint;
     3     ans:int64;
     4 
     5 begin
     6   readln(n);
     7   if n=1 then
     8   begin
     9     readln(x);
    10     if x=1 then writeln(0)
    11     else writeln(1);
    12     halt;
    13   end;
    14   for i:=1 to n do
    15   begin
    16     read(x);
    17     if (x<1) or (x>n) then
    18     begin
    19       writeln(0);
    20       halt;
    21     end;
    22     for j:=2 to x-1 do
    23       inc(c[j]);
    24     s:=s+x-1;
    25   end;
    26   if s<>n-2 then
    27   begin
    28     writeln(0);
    29     halt;
    30   end;
    31   ans:=1;
    32   for i:=2 to n-2 do
    33   begin
    34     ans:=ans*int64(i);
    35     for j:=2 to n do
    36     begin
    37       while (c[j]>0) and (ans mod j=0) do
    38       begin
    39         dec(c[j]);
    40         ans:=ans div j;
    41       end;
    42     end;
    43   end;
    44   writeln(ans);
    45 end.
    View Code
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  • 原文地址:https://www.cnblogs.com/phile/p/4473029.html
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