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  • HDU_2057——64位无符号16进制数的运算

    Problem Description
    There must be many A + B problems in our HDOJ , now a new one is coming. Give you two hexadecimal integers , your task is to calculate the sum of them,and print it in hexadecimal too. Easy ? AC it !
     
    Input
    The input contains several test cases, please process to the end of the file. Each case consists of two hexadecimal integers A and B in a line seperated by a blank. The length of A and B is less than 15.
     
    Output
    For each test case,print the sum of A and B in hexadecimal in one line.
     
    Sample Input
    +A -A +1A 12 1A -9 -1A -12 1A -AA
     
    Sample Output
    0 2C 11 -2C -90
     1 #include <cstdio>
     2 int main()
     3 {
     4    __int64 a,b,c;
     5    //十六进制数直接可以运算,字母X要大写 
     6    while(~scanf("%I64X%I64X",&a,&b))
     7       {
     8          //输入的时候是10...10101010
     9          //存储的时候是11...01010110补码形式 
    10          //输出的时候是FF...56
    11          //如果和的符号位是-的话,先-1再取反就变回原码形式 
    12          //然后再另外输出一个'-' 
    13          c=a+b;
    14          if(c<0)
    15             printf("-%I64X
    ",~(c-1));
    16          else
    17             printf("%I64X
    ",c);
    18       }
    19    return 0;
    20 }
    ——现在的努力是为了小时候吹过的牛B!!
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  • 原文地址:https://www.cnblogs.com/pingge/p/3185139.html
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