Given a set of candidate numbers (C) and a target number (T), find all unique combinations in C where the candidate numbers sums to T.
The same repeated number may be chosen from C unlimited number of times.
Note:
- All numbers (including target) will be positive integers.
- Elements in a combination (a1, a2, … , ak) must be in non-descending order. (ie, a1 ≤ a2 ≤ … ≤ ak).
- The solution set must not contain duplicate combinations.
For example, given candidate set 2,3,6,7
and target 7
,
A solution set is: [7]
[2, 2, 3]
比较经典的问题。
class Solution { public: void dfs(vector<int>& a,vector<vector<int>>&v,vector<int>&tmp,int id,int sum,int target){ if(sum>target)return ; if(sum==target){ v.push_back(tmp); return ; } for(int i=id;i<a.size();i++){ if(a[i]+sum>target)break;//重要的剪枝 tmp.push_back(a[i]); dfs(a,v,tmp,i,sum+a[i],target); tmp.pop_back(); } } vector<vector<int>> combinationSum(vector<int>& candidates, int target) { sort(candidates.begin(),candidates.end()); vector<vector<int>>v; vector<int>tmp; dfs(candidates,v,tmp,0,0,target); return v; } };