Given two strings s and t, determine if they are isomorphic.
Two strings are isomorphic if the characters in s can be replaced to get t.
All occurrences of a character must be replaced with another character while preserving the order of characters. No two characters may map to the same character but a character may map to itself.
For example,
Given "egg", "add", return true.
Given "foo", "bar", return false.
Given "paper", "title", return true.
思路:记录映射关系,如果不能匹配就返回false
class Solution {
public:
bool isIsomorphic(string s, string t) {
unordered_map<char, char> mp1;
unordered_map<char, char> mp2;
for (int i = 0; i < s.size(); ++i) {
if (mp1.count(s[i]) == 0 && mp2.count(t[i]) == 0) {
mp1[s[i]] = t[i];
mp2[t[i]] = s[i];
} else if (mp1.count(s[i]) == 0) {
if (s[i] != mp2[t[i]]) return false;
} else if (mp2.count(t[i]) == 0) {
if (t[i] != mp1[s[i]]) return false;
}
else {
if (mp2[t[i]] != s[i] || mp1[s[i]] != t[i]) return false;
}
}
return true;
}
};
//aacaa
//bbacc