PTA 估值一亿的AI核心代码

题面

比赛时被模拟题打自闭了，本来以为是个比较麻烦的模拟，实际上只要会C++的regex不到40行就能把这个题过掉了(orz smz）

regex是用来处理正则表达式，里面有个函数regex_replace(string s, regex re, string new_string)可以将s中满足正则表达式re的所有位置替换成new_string。

代码：

#include <bits/stdc++.h>
#include <regex>
using namespace std;
int main() {
	int n;
	scanf("%d", &n);
	getchar();
	while(n--) {
	     string s;
		getline(cin, s);
		cout << s << endl;
		s = regex_replace(s, regex(R"(s+)"), " ");
		if(s.front() == ' ') s.erase(s.begin());
		if(s.back() == ' ') s.pop_back();
		s = regex_replace(s, regex(R"( !)"), "!");	
		s = regex_replace(s, regex(R"( ,)"), ",");	
		s = regex_replace(s, regex(R"( .)"), ".");	
		s = regex_replace(s, regex(R"( ?)"), "?");	
		s = regex_replace(s, regex(R"( ')"), "'");
		for (auto &c : s) {
			if(c != 'I') c = tolower(c);
		}
		s = regex_replace(s, regex(R"(can you)"), "_I can");
		s = regex_replace(s, regex(R"(could you)"), "_I could");	
		s = regex_replace(s, regex(R"(I)"), "you");	
		s = regex_replace(s, regex(R"(me)"), "you");
		s = regex_replace(s, regex(R"(?)"), "!");
		s = regex_replace(s, regex(R"(_I)"), "I");	
		cout << "AI: " << s << endl;	
	}
}