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  • hdoj--1379--DNA Sorting(排序水题)

    

    DNA Sorting

    Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
    Total Submission(s): 2357    Accepted Submission(s): 1158


    Problem Description
    One measure of ``unsortedness'' in a sequence is the number of pairs of entries that are out of order with respect to each other. For instance, in the letter sequence ``DAABEC'', this measure is 5, since D is greater than four letters to its right and E is greater than one letter to its right. This measure is called the number of inversions in the sequence. The sequence ``AACEDGG'' has only one inversion (E and D)--it is nearly sorted--while the sequence ``ZWQM'' has 6 inversions (it is as unsorted as can be--exactly the reverse of sorted).

    You are responsible for cataloguing a sequence of DNA strings (sequences containing only the four letters A, C, G, and T). However, you want to catalog them, not in alphabetical order, but rather in order of ``sortedness'', from ``most sorted'' to ``least sorted''. All the strings are of the same length.


    This problem contains multiple test cases!

    The first line of a multiple input is an integer N, then a blank line followed by N input blocks. Each input block is in the format indicated in the problem description. There is a blank line between input blocks.

    The output format consists of N output blocks. There is a blank line between output blocks.

     

    Input
    The first line contains two integers: a positive integer n (0 < n <= 50) giving the length of the strings; and a positive integer m (1 < m <= 100) giving the number of strings. These are followed by m lines, each containing a string of length n.
     

    Output
    Output the list of input strings, arranged from ``most sorted'' to ``least sorted''. If two or more strings are equally sorted, list them in the same order they are in the input file.
     

    Sample Input
    1 10 6 AACATGAAGG TTTTGGCCAA TTTGGCCAAA GATCAGATTT CCCGGGGGGA ATCGATGCAT
     

    Sample Output
    CCCGGGGGGA AACATGAAGG GATCAGATTT ATCGATGCAT TTTTGGCCAA TTTGGCCAAA
     
    记得大一暑假的时候看到这个题也是一脸的懵逼
    #include<cstdio>
    #include<cstring>
    #include<algorithm>
    using namespace std;
    struct node
    {
    	char s[55];
    	int num,p;
    }q[1010];
    bool cmp(node s1,node s2)
    {
    	if(s1.p==s2.p)
    	return s1.num<s2.num;
    	return s1.p<s2.p;
    }
    int main()
    {
    	int t;
    	scanf("%d",&t);
    	while(t--)
    	{
    		int n,m;
    		scanf("%d%d",&n,&m);
    		for(int i=0;i<m;i++)
    		{
    			scanf("%s",q[i].s);
    			q[i].num=i;
    			q[i].p=0;
    			for(int j=0;j<n;j++)
    			{
    				for(int k=j+1;k<n;k++)
    				{
    					if(q[i].s[j]>q[i].s[k])
    					{
    						q[i].p++;
    					}
    				}
    			}
    		}
    		sort(q,q+m,cmp);
    		for(int i=0;i<m;i++)
    		printf("%s
    ",q[i].s);
    	}
    	return 0;
    }

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  • 原文地址:https://www.cnblogs.com/playboy307/p/5273379.html
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