Codeforces--630A--Again Twenty Five! （水题）



Again Twenty Five!

Time Limit: 500MS

Memory Limit: 65536KB

64bit IO Format: %I64d & %I64u

Submit Status

Description

The HR manager was disappointed again. The last applicant failed the interview the same way as 24 previous ones. "Do I give such a hard task?" — the HR manager thought. "Just raise number 5 to the power of n and get last two digits of the number. Yes, of course, n can be rather big, and one cannot find the power using a calculator, but we need people who are able to think, not just follow the instructions."

Could you pass the interview in the machine vision company in IT City?

Input

The only line of the input contains a single integer n (2 ≤ n ≤ 2·10¹⁸) — the power in which you need to raise number 5.

Output

Output the last two digits of 5ⁿ without spaces between them.

Sample Input

Input

2

Output

25

Sample Output

Hint

Source

Experimental Educational Round: VolBIT Formulas Blitz

输出5的n次方的后两位，n>=2，所以嘛，只可能是25

#include<iostream>
#include<cmath>
using namespace std;
int main()
{
	__int64 n;
	while(cin>>n)
	cout<<25<<endl;
	return 0;
}