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  • hdoj--2509--Be the Winner(尼姆博弈)

    Be the Winner

    Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
    Total Submission(s): 2718    Accepted Submission(s): 1487


    Problem Description
    Let's consider m apples divided into n groups. Each group contains no more than 100 apples, arranged in a line. You can take any number of consecutive apples at one time.
    For example "@@@" can be turned into "@@" or "@" or "@ @"(two piles). two people get apples one after another and the one who takes the last is
    the loser. Fra wants to know in which situations he can win by playing strategies (that is, no matter what action the rival takes, fra will win).
     

    Input
    You will be given several cases. Each test case begins with a single number n (1 <= n <= 100), followed by a line with n numbers, the number of apples in each pile. There is a blank line between cases.
     

    Output
    If a winning strategies can be found, print a single line with "Yes", otherwise print "No".
     

    Sample Input
    2 2 2 1 3
     

    Sample Output
    No Yes
    #include <stdio.h>
    #include <string.h>
    using namespace std;
    #define M 50
    int num[M];
    int main()
    {
       int i,ans,re,n;
       while(scanf("%d",&n)!=EOF)
       {
            ans=0,re=0;
            for(i=0;i<n;i++)
    		{
                scanf("%d",&num[i]);
                if(num[i]>1)
                ans++;
                re^=num[i];
            }
            if(ans)
    		{
                if(re)
                printf("Yes
    ");
                else
                printf("No
    ");
            }
            else 
    		{
                if(re)
                printf("No
    ");
                else
                printf("Yes
    ");
            }
       }
        return 0;
    }


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  • 原文地址:https://www.cnblogs.com/playboy307/p/5273783.html
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