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  • sql 求max和min,但是第二大,第二小怎么算?

    利用子查询,但这样速度较慢。

    SELECT 
     Baoming.id,
      Baoming.addtime AS '报名时间',
      CONCAT(Members.realname,Members.username) AS '客服姓名',
      Sem.name  AS `渠道来源`,
      CASE WHEN bmcs_fd_time IS NOT NULL THEN "分单" ELSE "未分单" END AS `是否分单`,
      CASE WHEN (SELECT COUNT(id) FROM come_go_phone_logs WHERE baoming_id = Baoming.id AND connect_status = 1  AND  call_mode = 2 ) > 0 THEN "接通" ELSE "未接通" END AS `是否接通`,
      (SELECT COUNT(id) FROM come_go_phone_logs WHERE baoming_id = Baoming.id   AND  call_mode = 2 ) AS '联系次数',
      (SELECT MIN(call_time) FROM come_go_phone_logs WHERE baoming_id = Baoming.id  AND  call_mode = 2 ) AS '第一次联系时间',
      (SELECT MIN(call_time) FROM come_go_phone_logs WHERE baoming_id = Baoming.id  AND  call_mode = 2  AND call_time>`第一次联系时间`) AS '第2次联系时间',
      (SELECT MIN(call_time) FROM come_go_phone_logs WHERE baoming_id = Baoming.id   AND  call_mode = 2  AND call_time>`第2次联系时间`) AS '第3次联系时间',
      (SELECT MIN(call_time) FROM come_go_phone_logs WHERE baoming_id = Baoming.id   AND  call_mode = 2  AND call_time>`第3次联系时间`) AS '第4次联系时间'
    FROM
      `baomings` AS Baoming 
     LEFT JOIN come_go_phone_logs AS Phone
     ON Phone.baoming_id = Baoming.id
     LEFT JOIN `members` AS Members
     ON Phone.seats_cs= Members.`id`
     LEFT JOIN `sem_sources` AS Sem
     ON Sem.j_name=Baoming.bm_laiyuan 
     WHERE Baoming.addtime >= '2017-07-01 00:00:00' 
      AND Baoming.is_fp = 1 
      AND Baoming.zx_tuijian = 1 
      AND Baoming.addtime <= '2017-07-11 23:59:59'
      AND Baoming.id IN ( SELECT  baoming_id ,COUNT(id) AS c FROM come_go_phone_logs WHERE  connect_status = 1  AND  call_mode = 2  ) 
      GROUP BY Baoming.id
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  • 原文地址:https://www.cnblogs.com/polax/p/7151970.html
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