转自：http://www.itpub.net/thread-1838303-1-1.html
1.中心移动（前1行、本行、后一行共3行）
SQL> with t as(select level mon,level*10 v from dual connect by level<=12)
2 select mon, sum(v) sv,avg(sum(v))over
3 (ORDER BY mon ROWS BETWEEN 1 PRECEDING AND 1 FOLLOWING) ma
4 from t
5 group by mon
6 order by mon;
MON SV MA
---------- ---------- ----------
1 10 15
2 20 20
3 30 30
4 40 40
5 50 50
6 60 60
7 70 70
8 80 80
9 90 90
10 100 100
11 110 110
12 120 115
已选择12行。
2.后移（当前行和前3行共4行）
SQL> with t as(select level mon,level*10 v from dual connect by level<=12)
2 select mon, sum(v) sv,avg(sum(v))over
3 (ORDER BY mon ROWS BETWEEN 3 PRECEDING AND CURRENT ROW) ma1
4 from t
5 group by mon
6 order by mon;
MON SV MA1
---------- ---------- ----------
1 10 10
2 20 15
3 30 20
4 40 25
5 50 35
6 60 45
7 70 55
8 80 65
9 90 75
10 100 85
11 110 95
12 120 105
已选择12行。
3.累计值（从第1月开始）
SQL> with t as(select level mon,level*10 v from dual connect by level<=12)
2 select mon, sum(v) sv,sum(sum(v))over
3 (ORDER BY mon ROWS BETWEEN UNBOUNDED PRECEDING AND CURRENT ROW) as1
4 from t
5 group by mon
6 order by mon;
MON SV AS1
---------- ---------- ----------
1 10 10
2 20 30
3 30 60
4 40 100
5 50 150
6 60 210
7 70 280
8 80 360
9 90 450
10 100 550
11 110 660
12 120 780
已选择12行。
4.当季累计(分别从1 4 7 10月开始)
SQL> with t as(select level mon,level*10 v from dual connect by level<=12)
2 select mon, sum(v) sv,sum(sum(v))over
3 (ORDER BY mon ROWS BETWEEN mod(mon-1,3) PRECEDING AND CURRENT ROW) as1
4 from t
5 group by mon
6 order by mon;
MON SV AS1
---------- ---------- ----------
1 10 10
2 20 30
3 30 60
4 40 40
5 50 90
6 60 150
7 70 70
8 80 150
9 90 240
10 100 100
11 110 210
12 120 330
已选择12行。
5.--窗口中第n(本例=2)个值
SQL> with t as(select level mon,level*10 v from dual connect by level<=12)
2 select mon, sum(v) sv,nth_value(sum(v),2)over
3 (ORDER BY mon ROWS BETWEEN UNBOUNDED PRECEDING AND UNBOUNDED FOLLOWING)nv2
4 from t
5 group by mon
6 order by mon;
MON SV NV2
---------- ---------- ----------
1 10 20
2 20 20
3 30 20
4 40 20
5 50 20
6 60 20
7 70 20
8 80 20
9 90 20
10 100 20
11 110 20
12 120 20
已选择12行。
SQL> --窗口中第n(本例=2)个值
SQL> with t as(select level mon,level*10 v from dual connect by level<=12)
2 select mon, sum(v) sv,nth_value(sum(v),2)over
3 (ORDER BY mon ROWS BETWEEN CURRENT ROW AND UNBOUNDED FOLLOWING)nv2
4 from t
5 group by mon
6 order by mon;
MON SV NV2
---------- ---------- ----------
1 10 20
2 20 30
3 30 40
4 40 50
5 50 60
6 60 70
7 70 80
8 80 90
9 90 100
10 100 110
11 110 120
12 120 NULL
已选择12行。
6.四等分，貌似与设想不符
SQL> with t as(select level mon,level*10 v from dual connect by level<=12)
2 select mon, sum(v) sv,ntile(4)over
3 (ORDER BY sum(mon) asc)nt4
4 from t
5 group by mon
6 order by mon;
MON SV NT4
---------- ---------- ----------
1 10 1
2 20 1
3 30 1
4 40 2
5 50 2
6 60 2
7 70 3
8 80 3
9 90 3
10 100 4
11 110 4
12 120 4
已选择12行。
7.累积分布
SQL> with t as(select level mon,level*10 v from dual connect by level<=12)
2 select mon, sum(v) sv,
3 cume_dist()over(ORDER BY sum(mon) asc)cd,
4 percent_rank()over(ORDER BY sum(mon) asc)cd
5 from t where mon<=5
6 group by mon
7 order by mon;
MON SV CD CD
---------- ---------- ---------- ----------
1 10 .2 0
2 20 .4 .25
3 30 .6 .5
4 40 .8 .75
5 50 1 1
8.反向累积
SQL> with t as(select level mon,level*10 v from dual connect by level<=12)
2 select
3 PERCENTILE_CONT(0.6) WITHIN GROUP (ORDER BY SUM(v) ASC)c,
4 PERCENTILE_DISC(0.6) WITHIN GROUP (ORDER BY SUM(v) ASC)d
5 from t where mon<=5
6 group by mon
7 ;
C D
---------- ----------
34 30