zoukankan      html  css  js  c++  java
  • luogu2526 [SHOI2001]小狗散步

    注意一个景点只能去一次。

    #include <iostream>
    #include <cstring>
    #include <cstdio>
    #include <queue>
    #include <cmath>
    using namespace std;
    int n, m, xx[205], yy[205], hea[205], ss, tt, cnt, lev[205], maxFlow;
    const int oo=0x3f3f3f3f;
    queue<int> d;
    struct Edge{
    	int too, nxt, val;
    }edge[45005];
    double dis(int i, int j){
    	return sqrt((xx[i]-xx[j])*(xx[i]-xx[j])+(yy[i]-yy[j])*(yy[i]-yy[j]));
    }
    void add_edge(int fro, int too, int val){
    	edge[cnt].nxt = hea[fro];
    	edge[cnt].too = too;
    	edge[cnt].val = val;
    	hea[fro] = cnt++;
    }
    void addEdge(int fro, int too, int val){
    	add_edge(fro, too, val);
    	add_edge(too, fro, 0);
    }
    bool bfs(){
    	memset(lev, 0, sizeof(lev));
    	lev[ss] = 1;
    	d.push(ss);
    	while(!d.empty()){
    		int x=d.front();
    		d.pop();
    		for(int i=hea[x]; i!=-1; i=edge[i].nxt){
    			int t=edge[i].too;
    			if(!lev[t] && edge[i].val>0){
    				lev[t] = lev[x] + 1;
    				d.push(t);
    			}
    		} 
    	}
    	return lev[tt]!=0;
    }
    int dfs(int x, int lim){
    	if(x==tt)	return lim;
    	int addFlow=0;
    	for(int i=hea[x]; i!=-1 && addFlow<lim; i=edge[i].nxt){
    		int t=edge[i].too;
    		if(lev[t]==lev[x]+1 && edge[i].val>0){
    			int tmp=dfs(t, min(lim-addFlow, edge[i].val));
    			edge[i].val -= tmp;
    			edge[i^1].val += tmp;
    			addFlow += tmp;
    		}
    	}
    	return addFlow;
    }
    void dinic(){
    	while(bfs())	maxFlow += dfs(ss, oo);
    }
    int main(){
    	memset(hea, -1, sizeof(hea));
    	cin>>n>>m;
    	for(int i=1; i<=n+m; i++)	scanf("%d %d", &xx[i], &yy[i]);
    	ss = 0; tt = n + m + 1;
    	for(int i=1; i<=n; i++){
    		addEdge(ss, i, 1);
    		if(i==n)	break;
    		double disii=dis(i, i+1);
    		for(int j=n+1; j<=n+m; j++)
    			if(dis(i,j)+dis(j,i+1)<disii*2.0+1e-7)
    				addEdge(i, j, 1);
    	}
    	for(int j=n+1; j<=n+m; j++)
    		addEdge(j, tt, 1);
    	dinic();
    	cout<<n+maxFlow<<endl;
    	for(int i=1; i<=n; i++){
    		printf("%d %d ", xx[i], yy[i]);
    		for(int j=hea[i]; j!=-1; j=edge[j].nxt){
    			if(edge[j^1].val && edge[j].too!=ss){
    				int t=edge[j].too;
    				printf("%d %d ", xx[t], yy[t]);
    			}
    		}
    	}
    	return 0;
    }
    
  • 相关阅读:
    工作笔记(2017/02/15)
    JQuery基本知识(3)
    C#基础之操作字符串的方法
    JQuery基础知识(2)
    JQuery基础知识(1)
    将前台input中的数据异步传到后台并存入数据库
    C#基本知识零散总结
    ASP.NET中的C#基础知识
    C#练习
    将JSON数组显示前台Table中
  • 原文地址:https://www.cnblogs.com/poorpool/p/8317387.html
Copyright © 2011-2022 走看看