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  • 有上下界的网络流 loj115 loj116 loj 117

    参考文章

    无源汇有上下界的可行流
    有源汇有上下界的最大流
    有源汇有上下界的最小流

    无源汇有上下界可行流

    以 loj115 为例。
    剥离出必要边与自由边。

    #include <iostream>
    #include <cstring>
    #include <cstdio>
    #include <queue>
    using namespace std;
    int n, m, ss, tt, hea[205], uu, vv, ww, xx, cnt, tot, maxFlow, lev[205];
    const int oo=0x3f3f3f3f;
    queue<int> d;
    struct Edge{
    	int too, nxt, val, lim;
    }edge[100005];
    void add_edge(int fro, int too, int val, int lim){
    	edge[cnt].nxt = hea[fro];
    	edge[cnt].too = too;
    	edge[cnt].lim = lim;
    	edge[cnt].val = val;
    	hea[fro] = cnt++;
    }
    void addEdge(int fro, int too, int val, int lim){
    	add_edge(fro, too, val, lim);
    	add_edge(too, fro, 0, lim);
    }
    bool bfs(){
    	memset(lev, 0, sizeof(lev));
    	lev[ss] = 1;
    	d.push(ss);
    	while(!d.empty()){
    		int x=d.front();
    		d.pop();
    		for(int i=hea[x]; i!=-1; i=edge[i].nxt){
    			int t=edge[i].too;
    			if(!lev[t] && edge[i].val>0){
    				lev[t] = lev[x] + 1;
    				d.push(t);
    			}
    		}
    	}
    	return lev[tt]!=0;
    }
    int dfs(int x, int lim){
    	if(x==tt)	return lim;
    	int addFlow=0;
    	for(int i=hea[x]; i!=-1 && addFlow<lim; i=edge[i].nxt){
    		int t=edge[i].too;
    		if(lev[t]==lev[x]+1 && edge[i].val>0){
    			int tmp=dfs(t, min(lim-addFlow, edge[i].val));
    			edge[i].val -= tmp;
    			edge[i^1].val += tmp;
    			addFlow += tmp;
    		}
    	}
    	return addFlow;
    }
    void dinic(){
    	while(bfs())	maxFlow += dfs(ss, oo);
    }
    int main(){
    	memset(hea, -1, sizeof(hea));
    	cin>>n>>m;
    	ss = 0; tt = n + 1;
    	for(int i=1; i<=m; i++){
    		scanf("%d %d %d %d", &uu, &vv, &ww, &xx);
    		addEdge(uu, vv, xx-ww, ww);
    		addEdge(ss, vv, ww, ww);
    		addEdge(uu, tt, ww, ww);//有一种优化是统计每个点流入下界与流出下界的差,然后根据差的正负决定是连ss还是tt
    		tot += ww;
    	}
    	dinic();
    	if(maxFlow<tot)	printf("NO
    ");
    	else{
    		printf("YES
    ");
    		for(int i=0; i<cnt; i+=6)
    			printf("%d
    ", edge[i].lim+edge[i^1].val);
    	}
    	return 0;
    }
    

    有源汇有上下界最大流

    以 loj116 为例。

    #include <iostream>
    #include <cstring>
    #include <cstdio>
    #include <queue>
    using namespace std;
    struct Edge{
        int too, nxt, val, lim;
    }edge[60005];
    int n, m, ss, tt, sss, ttt, hea[255], cnt, lev[255], uu, vv, ww, xx;
    int maxFlow, tot;
    const int oo=0x3f3f3f3f;
    queue<int> d;
    void add_edge(int fro, int too, int val, int lim){
        edge[cnt].nxt = hea[fro];
        edge[cnt].too = too;
        edge[cnt].val = val;
        edge[cnt].lim = lim;
        hea[fro] = cnt++;
    }
    void addEdge(int fro, int too, int val, int lim){
        add_edge(fro, too, val-lim, lim);
        add_edge(too, fro, 0, lim);
        add_edge(sss, too, lim, lim);
        add_edge(too, sss, 0, lim);
        add_edge(fro, ttt, lim, lim);
        add_edge(ttt, fro, 0, lim);
    }
    bool bfs(int fro, int too){
        memset(lev, 0, sizeof(lev));
        lev[fro] = 1;
        d.push(fro);
        while(!d.empty()){
            int x=d.front();
            d.pop();
            for(int i=hea[x]; i!=-1; i=edge[i].nxt){
                int t=edge[i].too;
                if(!lev[t] && edge[i].val>0){
                    lev[t] = lev[x] + 1;
                    d.push(t);
                }
            }
        }
        return lev[too]!=0;
    }
    int dfs(int fro, int too, int lim){
        if(fro==too)    return lim;
        int addFlow=0;
        for(int i=hea[fro]; i!=-1 && addFlow<lim; i=edge[i].nxt){
            int t=edge[i].too;
            if(lev[t]==lev[fro]+1 && edge[i].val>0){
                int tmp=dfs(t, too, min(lim-addFlow, edge[i].val));
                edge[i].val -= tmp;
                edge[i^1].val += tmp;
                addFlow += tmp;
            }
        }
        return addFlow;
    }
    void dinic(int fro, int too){
        maxFlow = 0;
        while(bfs(fro, too))    maxFlow += dfs(fro, too, oo);
    }
    int main(){
        cin>>n>>m>>ss>>tt;
        memset(hea, -1, sizeof(hea));
        sss = 0; ttt = n + 1;
        for(int i=1; i<=m; i++){
            scanf("%d %d %d %d", &uu, &vv, &ww, &xx);
            addEdge(uu, vv, xx, ww);
            tot += ww;
        }
        addEdge(tt, ss, oo, 0);
        dinic(sss, ttt);
        if(maxFlow<tot) printf("please go home to sleep
    ");
        else{
            dinic(ss, tt);
            cout<<maxFlow<<endl;
        }
        return 0;
    }
    

    有源汇有上下界最小流

    以 loj117 为例

    #include <iostream>
    #include <cstring>
    #include <cstdio>
    #include <queue>
    using namespace std;
    typedef long long ll;
    int uu, vv, n, m, ss, tt, sss, ttt, hea[50105], cnt, lev[50105], cur[50105];
    ll du[50105], ww, xx, tot, minFlow;
    const ll oo=0x3f3f3f3f3f3f3f3f;
    queue<int> d;
    struct Edge{
    	int too, nxt;
    	ll val;
    }edge[400005];
    void add_edge(int fro, int too, ll val){
    	edge[cnt].nxt = hea[fro];
    	edge[cnt].too = too;
    	edge[cnt].val = val;
    	hea[fro] = cnt++;
    }
    void addEdge(int fro, int too, ll val){
    	add_edge(fro, too, val);
    	add_edge(too, fro, 0);
    }
    bool bfs(){
    	memset(lev, 0, sizeof(lev));
    	lev[sss] = 1;
    	d.push(sss);
    	while(!d.empty()){
    		int x=d.front();
    		d.pop();
    		for(int i=hea[x]; i!=-1; i=edge[i].nxt){
    			int t=edge[i].too;
    			if(!lev[t] && edge[i].val>0){
    				lev[t] = lev[x] + 1;
    				d.push(t);
    			}
    		}
    	}
    	return lev[ttt]!=0;
    }
    ll dfs(int x, ll lim){
    	if(x==ttt)	return lim;
    	ll addFlow=0;
    	for(int &i=cur[x]; i!=-1; i=edge[i].nxt){
    		int t=edge[i].too;
    		if(lev[t]==lev[x]+1 && edge[i].val>0){
    			ll tmp=dfs(t, min(lim-addFlow, edge[i].val));
    			edge[i].val -= tmp;
    			edge[i^1].val += tmp;
    			addFlow += tmp;
    			if(addFlow==lim)	break;//注意,当前弧优化的addFlow的限制一定要在这里写。
    		}
    	}
    	return addFlow;
    }
    void dinic(){
    	while(bfs()){
    		for(int i=sss; i<=ttt; i++)	cur[i] = hea[i];
    		minFlow += dfs(sss, oo);
    	}
    }
    int main(){
    	memset(hea, -1, sizeof(hea));
    	cin>>n>>m>>ss>>tt;
    	sss = 0; ttt = n + 1;
    	for(int i=1; i<=m; i++){
    		scanf("%d %d %lld %lld", &uu, &vv, &ww, &xx);
    		addEdge(uu, vv, xx-ww);
    		du[uu] -= ww;
    		du[vv] += ww;
    	}
    	for(int i=1; i<=n; i++){
    		if(du[i]>0)	tot += du[i], addEdge(sss, i, du[i]);
    		else if(du[i]<0)	addEdge(i, ttt, -du[i]);
    	}
    	dinic();
    	addEdge(tt, ss, oo);
    	dinic();
    	if(minFlow<tot)	printf("please go home to sleep
    ");
    	else	printf("%lld
    ", edge[cnt-1].val);
    	return 0;
    }
    
    
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  • 原文地址:https://www.cnblogs.com/poorpool/p/8360180.html
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