[C] Struct Test

#include <stdio.h>
#include <string.h>
struct Person
{
    char name[24];
    char character[30];
    int age;
    struct Birthday
    {
        int day;
        char month[10];
        int year;
    } birthday;
};
int main()
{
    struct Person man1;
    strcpy(man1.name, "Jerry Seinfeld");
    strcpy(man1.character, "fastidious");
    man1.age = 56;
    man1.birthday.day = 4;
    strcpy(man1.birthday.month, "June");// = 6;
    man1.birthday.year = 2020;
    printf("My name is %s, I was born on %s-%d-%d, so I'm %d years old now. And my friends always complain I'm too %s.
", 
        man1.name, man1.birthday.month, man1.birthday.day, man1.birthday.year, man1.age, man1.character);
    return 0;
}

输出结果为:

My name is Jerry Seinfeld, I was born on June-4-2020, so I'm 56 years old now. And my friends always complain I'm too fastidious.

虽然上面的初始化太复杂，但是可以选择性的赋值

#include <stdio.h>
struct Person
{
    char name[24];
    char character[30];
    int age;
    struct Birthday //嵌套一个struct，Birthday也可以删掉，直接写成struct,因为Birthday根本没用到，用的只是birthday
    {
        int day;
        char month[10];
        int year;
    } birthday;
};
int main()
{
    struct Person man1 = {"Jerry Seinfeld", "fastidious", 56, 4, "June", 2020}; //注意对应好，如果缺少，int默认补0， char默认空格
    printf("My name is %s, I was born on %s-%d-%d, so I'm %d years old now. And my friends always complain I'm too %s.
", 
        man1.name, man1.birthday.month, man1.birthday.day, man1.birthday.year, man1.age, man1.character);
    return 0;
}