zoukankan      html  css  js  c++  java
  • Entity Framework Code-First(6):Database Initialization

    Database Initialization:

    We have seen that Code First creates a database automatically in the Simple Code First Examplesection. Here, we will learn how Code first decides the database name and server while initializing a database.

    The following figure shows a database initialization workflow, based on the parameter passed in the base constructor of context class, which is derived from DbContext:

    Entity Framework code-first database initialization

    As per the above figure, base constructor of the context class can have the following parameter.

    1. No Parameter
    2. Database Name
    3. Connection String Name

    No Parameter:

    If you do not specify the parameter in the base constructor of the context class then it creates a database in your local SQLEXPRESS server with a name that matches your {Namespace}.{Context class name}. For example, Code First will create a database named SchoolDataLayer.Context for the following context class:

    namespace SchoolDataLayer
    {
        public class Context: DbContext 
        {
            public Context(): base()
            {
                
            }
        }
    }

    Database Name:

    You can also specify the database name as a parameter in a base constructor of the context class. If you specify a database name parameter, then Code First creates a database with the name you specified in the base constructor in the local SQLEXPRESS database server. For example, Code First will create a database named MySchoolDB for the following context class.

    namespace SchoolDataLayer
    {
        public class Context: DbContext 
        {
            public Context(): base("MySchoolDB") 
            {
                       
            }
        }
    }

    ConnectionString Name:

    You can also define connection string in app.config or web.config and specify connection string name starting with "name=" in the base constructor of the context class. Consider the following example where we pass name=SchoolDBConnectionString parameter in the base constructor.

    namespace SchoolDataLayer
    {
        public class Context: DbContext 
        {
            public SchoolDBContext() : base("name=SchoolDBConnectionString") 
            {
            }
        }
    }

    App.config:

    <?xml version="1.0" encoding="utf-8" ?>
    <configuration>
        <connectionStrings>
        <add name="SchoolDBConnectionString" 
        connectionString="Data Source=.;Initial Catalog=SchoolDB-ByConnectionString;Integrated Security=true" 
        providerName="System.Data.SqlClient"/>
        </connectionStrings>
    </configuration>

    In the above context class, we specify a connection string name as a parameter. Please note that connection string name should start with "name=" otherwise, it will consider it as a database name. The database name in the connection string in app.config is SchoolDB-ByConnectionString. Code-First will create a new SchoolDB-ByConnectionString database or use existing SchoolDB-ByConnectionString database at local SQL Server. Make sure that you include providerName = "System.Data.SqlClient" in the connection string.

    Thus, Code-First use the base constructor parameter to initialize a database.

  • 相关阅读:
    SSH框架中使用Oracle数据库转换为SQLServer的相关配置和注意事项
    MYSQL性能优化系统整理
    PHP时间处理
    debian9 VirtualBox rc=-1908的错误
    https://snapcraft.io/store
    中文转拼音 pinyin4j的使用
    java对象转数组|数组转对象
    Deflater 压缩解压
    spring的RestTemplate连接池相关配置
    spring获取指定包下面的所有类
  • 原文地址:https://www.cnblogs.com/purplefox2008/p/5644070.html
Copyright © 2011-2022 走看看