例如输入:
0 3 5 7 -1
input:0123456789
output:0123567
程序分析:
输入两段字串间隔如:(0 3) (5 7) -1是结束符
/* ** This program reads input lines from the standard input and prints ** each input line, followed by just some portions of the lines, to ** the standard output. ** ** The first input is a list of column numbers, which ends with a ** negative number. The column numbers are paired and specify ** ranges of columns from the input line that are to be printed. ** For example, 0 3 10 12 -1 indicates that only columns 0 through 3 ** and columns 10 through 12 will be printed. */ #include <stdio.h> #include <stdlib.h> #include <string.h> #define MAX_COLS 20 /* max # of columns to process */ #define MAX_INPUT 1000 /* max len of input & output lines */ int read_column_numbers( int columns[], int max ); void rearrange( char *output, char const *input, int n_columns, int const columns[] ); int main( void ) { int n_columns; /* # of columns to process */ int columns[MAX_COLS]; /* the columns to process */ char input[MAX_INPUT]; /* array for input line */ char output[MAX_INPUT]; /* array for output line */ /* ** Read the list of column numbers */ n_columns = read_column_numbers( columns, MAX_COLS ); /* ** Read, process and print the remaining lines of input. */ while( gets( input ) != NULL ){ printf( "Original input : %s\n", input ); rearrange( output, input, n_columns, columns ); printf( "Rearranged line: %s\n", output ); } return EXIT_SUCCESS; } /* ** Read the list of column numbers, ignoring any beyond the specified ** maximum. */ int read_column_numbers( int columns[], int max ) { int num = 0; int ch; /* ** Get the numbers, stopping at eof or when a number is < 0. */ while( num < max && scanf( "%d", &columns[num] ) == 1 && columns[num] >= 0 ) num += 1; /* ** Make sure we have an even number of inputs, as they are ** supposed to be paired. */ if( num % 2 != 0 ){ puts( "Last column number is not paired." ); exit( EXIT_FAILURE ); } /* ** Discard the rest of the line that contained the final ** number. */ while( (ch = getchar()) != EOF && ch != '\n' ) ; return num; } /* ** Process a line of input by concatenating the characters from ** the indicated columns. The output line is then NUL terminated. */ void rearrange( char *output, char const *input, int n_columns, int const columns[] ) { int col; /* subscript for columns array */ int output_col; /* output column counter */ int len; /* length of input line */ len = strlen( input ); output_col = 0; /* ** Process each pair of column numbers. */ for( col = 0; col < n_columns; col += 2 ){ int nchars = columns[col + 1] - columns[col] + 1; /* ** If the input line isn't this long or the output ** array is full, we're done. */ if( columns[col] >= len || output_col == MAX_INPUT - 1 ) break; /* ** If there isn't room in the output array, only copy ** what will fit. */ if( output_col + nchars > MAX_INPUT - 1 ) nchars = MAX_INPUT - output_col - 1; /* ** Copy the relevant data. */ strncpy( output + output_col, input + columns[col], nchars ); output_col += nchars; } output[output_col] = '\0'; }