select ifnull ( (select distinct Salary from Employee order by Salary desc limit 1,1), null )as 'SecondHighestSalary'
编写一个 SQL 查询,获取 Employee 表中第二高的薪水(Salary) 。
+----+--------+
| Id | Salary |
+----+--------+
| 1 | 100 |
| 2 | 200 |
| 3 | 300 |
+----+--------+
例如上述 Employee 表,SQL查询应该返回 200 作为第二高的薪水。如果不存在第二高的薪水,那么查询应返回 null。
+---------------------+
| SecondHighestSalary |
+---------------------+
| 200 |
+---------------------+
来源:力扣(LeetCode)
链接:https://leetcode-cn.com/problems/second-highest-salary
著作权归领扣网络所有。商业转载请联系官方授权,非商业转载请注明出处。
如果把第二高,更新为第N高的薪水
CREATE FUNCTION getNthHighestSalary(N INT) RETURNS INT BEGIN SET N = N-1; IF N < 0 THEN RETURN NULL; ELSE RETURN ( # Write your MySQL query statement below. SELECT IFNULL( ( SELECT DISTINCT Salary FROM Employee ORDER BY Salary DESC LIMIT N, 1 ), NULL) AS getNthHighestSalary ); END IF; END