原文链接
https://segmentfault.com/q/1010000010352622
希望将下列数组中的sh替换成沪,sz替换成深
var stooges = [ {label:1,value:1,placeCode: 'sh', stock_code: 40}, {label:1,value:1,placeCode: 'sh', stock_code: 50}, {label:1,value:1,placeCode: 'sz', stock_code: 60,status:1}, {label:1,value:1,placeCode: 'sz', stock_code: 39,status:1} ];
我能想到的:
1 var stooges = [ 2 {label: 1, value: 1, placeCode: 'sh', stock_code: 40}, 3 {label: 1, value: 1, placeCode: 'sh', stock_code: 50}, 4 {label: 1, value: 1, placeCode: 'sz', stock_code: 60, status: 1}, 5 {label: 1, value: 1, placeCode: 'sz', stock_code: 39, status: 1} 6 ]; 7 8 for (var i = 0; i < stooges.length; i++) { 9 var item = stooges[i]; 10 if (item.placeCode == "sh") { 11 item.placeCode = "沪"; 12 } 13 if (item.placeCode == "sz") { 14 item.placeCode = "深"; 15 } 16 } 17 写个for循环遍历一下,从第一个对象开始,发现对应的placeCode是sh则更新成文字沪,发现对应的placeCode是sz则更新成文字深,一直到最后一个对象
最简便:
1 for(var i=0;i<stooges.length;i++){ 2 stooges[i].placeCode === 'sh'?stooges[i].placeCode = '沪': stooges[i].placeCode = '深' 3 }
第二种
var maps= new Map([['sh','沪'],['sz','深圳']]); stooges = stooges.map(element =>{ element.placeCode = maps.get(element.placeCode); return element; });
第三种
var toStr = { sh : '沪', sz : '深' }; stooges.map(function(value){ var placeCode = value.placeCode; value.placeCode = toStr[placeCode] ? toStr[placeCode] : placeCode; return value; });
再次定义一个对象,
定义一个返回vlaue的函数;
map一下