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  • [leedcode 133] Clone Graph

    Clone an undirected graph. Each node in the graph contains a label and a list of its neighbors.


    OJ's undirected graph serialization:

    Nodes are labeled uniquely.

    We use # as a separator for each node, and , as a separator for node label and each neighbor of the node.

    As an example, consider the serialized graph {0,1,2#1,2#2,2}.

    The graph has a total of three nodes, and therefore contains three parts as separated by #.

    1. First node is labeled as 0. Connect node 0 to both nodes 1 and 2.
    2. Second node is labeled as 1. Connect node 1 to node 2.
    3. Third node is labeled as 2. Connect node 2 to node 2 (itself), thus forming a self-cycle.

    Visually, the graph looks like the following:

           1
          / 
         /   
        0 --- 2
             / 
             \_/
    /**
     * Definition for undirected graph.
     * class UndirectedGraphNode {
     *     int label;
     *     List<UndirectedGraphNode> neighbors;
     *     UndirectedGraphNode(int x) { label = x; neighbors = new ArrayList<UndirectedGraphNode>(); }
     * };
     */
    public class Solution {
        使用深度优先搜索。这样可以递归实现,如果是宽度优先,就要额外使用queue容器。
        关键点:
        1 这里的clone需要深度拷贝,就是要使用new操作了
        2 防止回路无限循环,就要使用hash表,这里使用map记录访问过的节点。因为这里的label应该是唯一的才对,所以可以直接使用label作为关键字就可以。
        public UndirectedGraphNode cloneGraph(UndirectedGraphNode node) {
            if(node==null) return null;
            HashMap<Integer,UndirectedGraphNode> map=new HashMap<Integer,UndirectedGraphNode>();
            return clone(node,map);
        }
        public UndirectedGraphNode clone(UndirectedGraphNode node,HashMap<Integer,UndirectedGraphNode> map){
            if(map.containsKey(node.label)) return map.get(node.label);
            UndirectedGraphNode newNode=new UndirectedGraphNode(node.label);
             map.put(node.label,newNode);////注意标记的位置
            for(UndirectedGraphNode n:node.neighbors){
                newNode.neighbors.add(clone(n,map));/////
            }     
            return newNode;
        }
    }
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  • 原文地址:https://www.cnblogs.com/qiaomu/p/4677942.html
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