zoukankan      html  css  js  c++  java
  • [HDU 5964 平行四边形] (解析几何)

    [HDU 5964 平行四边形] (解析几何)

    题面:

    思路:

    注意:需要快读。

    代码:

    #include <iostream>
    #include <cstdio>
    #include <algorithm>
    #include <bits/stdc++.h>
    #define ALL(x) (x).begin(), (x).end()
    #define sz(a) int(a.size())
    #define rep(i,x,n) for(int i=x;i<n;i++)
    #define repd(i,x,n) for(int i=x;i<=n;i++)
    #define pii pair<int,int>
    #define pll pair<long long ,long long>
    #define gbtb ios::sync_with_stdio(false),cin.tie(0),cout.tie(0)
    #define MS0(X) memset((X), 0, sizeof((X)))
    #define MSC0(X) memset((X), '', sizeof((X)))
    #define pb push_back
    #define mp make_pair
    #define fi first
    #define se second
    #define eps 1e-6
    #define chu(x)  if(DEBUG_Switch) cout<<"["<<#x<<" "<<(x)<<"]"<<endl
    #define du3(a,b,c) scanf("%d %d %d",&(a),&(b),&(c))
    #define du2(a,b) scanf("%d %d",&(a),&(b))
    #define du1(a) scanf("%d",&(a));
    using namespace std;
    typedef long long ll;
    ll gcd(ll a, ll b) {return b ? gcd(b, a % b) : a;}
    ll lcm(ll a, ll b) {return a / gcd(a, b) * b;}
    ll powmod(ll a, ll b, ll MOD) { if (a == 0ll) {return 0ll;} a %= MOD; ll ans = 1; while (b) {if (b & 1) {ans = ans * a % MOD;} a = a * a % MOD; b >>= 1;} return ans;}
    ll poww(ll a, ll b) { if (a == 0ll) {return 0ll;} ll ans = 1; while (b) {if (b & 1) {ans = ans * a ;} a = a * a ; b >>= 1;} return ans;}
    void Pv(const vector<int> &V) {int Len = sz(V); for (int i = 0; i < Len; ++i) {printf("%d", V[i] ); if (i != Len - 1) {printf(" ");} else {printf("
    ");}}}
    void Pvl(const vector<ll> &V) {int Len = sz(V); for (int i = 0; i < Len; ++i) {printf("%lld", V[i] ); if (i != Len - 1) {printf(" ");} else {printf("
    ");}}}
    inline long long readll() {long long tmp = 0, fh = 1; char c = getchar(); while (c < '0' || c > '9') {if (c == '-') { fh = -1; } c = getchar();} while (c >= '0' && c <= '9') { tmp = tmp * 10 + c - 48, c = getchar(); } return tmp * fh;}
    inline int readint() {int tmp = 0, fh = 1; char c = getchar(); while (c < '0' || c > '9') {if (c == '-') { fh = -1; } c = getchar();} while (c >= '0' && c <= '9') { tmp = tmp * 10 + c - 48, c = getchar(); } return tmp * fh;}
    void pvarr_int(int *arr, int n, int strat = 1) {if (strat == 0) {n--;} repd(i, strat, n) {printf("%d%c", arr[i], i == n ? '
    ' : ' ');}}
    void pvarr_LL(ll *arr, int n, int strat = 1) {if (strat == 0) {n--;} repd(i, strat, n) {printf("%lld%c", arr[i], i == n ? '
    ' : ' ');}}
    const int maxn = 1000010;
    const int inf = 0x3f3f3f3f;
    /*** TEMPLATE CODE * * STARTS HERE ***/
    #define DEBUG_Switch 0
    int n;
    ll a, b, c, d;
    ll f(ll x, ll y)
    {
        return  a * c * x * x +  b * d * y * y + ( a * d +  b * c) * x * y;
    }
    
    int main()
    {
    #if DEBUG_Switch
        freopen("D:\code\input.txt", "r", stdin);
    #endif
        //freopen("D:\code\output.txt","w",stdout);
        while (~scanf("%lld %lld %lld %lld", &a, &b, &c, &d)) {
            n = readint();
            ll f1 = -1e18;
            ll f2 = 1e18;
            while (n--) {
                ll x = readll();
                ll y = readll();
                ll val = f(x, y);
                f1 = max(f1, val);
                f2 = min(f2, val);
            }
            double ans = (f1 - f2) * 1.0 / fabs(a * d - b * c);
            printf("%.f
    ", ans );
        }
        return 0;
    }
    
    
    
  • 相关阅读:
    洛谷P1455 搭配购买
    洛谷1341 无序字母对
    打击犯罪
    Cheese
    [noip2002] 产生数
    分治算法-----二分求最大最小
    yl 练习
    cj 练习
    雅礼2018-03-19洛谷作业 2
    雅礼2018-03-19洛谷作业
  • 原文地址:https://www.cnblogs.com/qieqiemin/p/14027188.html
Copyright © 2011-2022 走看看