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  • 11. Container With Most Water (JAVA)

    Given n non-negative integers a1, a2, ..., an , where each represents a point at coordinate (i, ai). n vertical lines are drawn such that the two endpoints of line i is at (i, ai) and (i, 0). Find two lines, which together with x-axis forms a container, such that the container contains the most water.

    Note: You may not slant the container and n is at least 2.

    Example:

    Input: [1,8,6,2,5,4,8,3,7]
    Output: 49

    class Solution {
        public int maxArea(int[] height) {
            return calMax(height, 0, height.length-1, 0);
        }
        
        public int calMax(int[] height, int left, int right, int max){
            if(left >= right) return max;
    
            if(height[left] > height[right]){
                int area = (right-left) * height[right];
                return calMax(height, left, right-1, Math.max(area,max));
            }
            else{
                int area = (right-left) * height[left];
                return calMax(height, left+1, right, Math.max(area,max));
            }
        }
    }

    解题思路:两个指针分别指向左右两个位置,保留高的那个,矮的那个往中间移动。(Greedy:总是寻找高的柱子)

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  • 原文地址:https://www.cnblogs.com/qionglouyuyu/p/10766321.html
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