Write a program to solve a Sudoku puzzle by filling the empty cells.
Empty cells are indicated by the character '.'
.
You may assume that there will be only one unique solution.
A sudoku puzzle...
...and its solution numbers marked in red.
class Solution { public: void solveSudoku(vector<vector<char>> &board) { int line=0,column=-1; findNextEmpty(board,line,column); backtracking(board,line,column); } bool backtracking(vector<vector<char>> &board,int line, int column) { int i=line, j = column; for(int k = 1; k<=9; k++) { if(!isValid(board,line,column,k+'0')) continue; board[line][column] = k+'0'; if(!findNextEmpty(board,line,column)) return true; //if no empty cell is found if(backtracking(board,line,column)) return true; //backTracking line = i; column = j; } //backTracking board[line][column] = '.'; return false; //if no valid number is found } //为回溯法写一个独立的check函数 bool isValid(vector<vector<char>> &board, int line, int column, char value) { //check九宫格的一个格 int upperBoard = line/3 * 3; int leftBoard = column/3 * 3; for(int i = 0; i<3; i++) { for(int j = 0; j<3; j++) { if(board[upperBoard+i][leftBoard+j] == value) return false; } } //check 列 for(int i = 0; i<9; i++) { if(board[line][i] == value) return false; } //check行 for(int i = 0; i<9; i++) { if(board[i][column] == value) return false; } return true; } bool findNextEmpty(vector<vector<char>> &board, int &line, int &column){ int i,j; for(j = column+1; j < 9; j++){ if(board[line][j]!='.') continue; column=j; return true; } for(i = line+1; i < 9; i++){ for(j = 0; j < 9; j++){ if(board[i][j]!='.') continue; line = i; column=j; return true; } } return false; } };