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  • 2. Add Two Numbers

    You are given two linked lists representing two non-negative numbers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list.

    Input: (2 -> 4 -> 3) + (5 -> 6 -> 4)
    Output: 7 -> 0 -> 8

    /**
     * Definition for singly-linked list.
     * public class ListNode {
     *     int val;
     *     ListNode next;
     *     ListNode(int x) { val = x; }
     * }
     */
    public class Solution {
        public ListNode addTwoNumbers(ListNode l1, ListNode l2) {
            ListNode pl1 = l1;
            ListNode pl2 = l2;
            ListNode head = new ListNode(0);
            ListNode p = head;
            int carry = 0;
            int sum;
            while(pl1!=null && pl2!=null){
                sum = pl1.val + pl2.val + carry; 
                carry = sum>=10?1:0;
                p.next = new ListNode(sum%10);
                p = p.next;
                pl1 = pl1.next;
                pl2 = pl2.next;
            }
            while(pl1!=null){
                sum = pl1.val + carry; 
                carry = sum>=10?1:0;
                p.next = new ListNode(sum%10);
                p = p.next;
                pl1 = pl1.next;
            }
            while(pl2!=null){
                sum = pl2.val + carry; 
                carry = sum>=10?1:0;
                p.next = new ListNode(sum%10);
                p = p.next;
                pl2 = pl2.next;
            }
            if(carry==1){
                p.next = new ListNode(carry);
            }
            return head.next;
        }
    }
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  • 原文地址:https://www.cnblogs.com/qionglouyuyu/p/5451200.html
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