zoukankan      html  css  js  c++  java
  • Codeforces Round #478 C. Valhalla Siege

    C. Valhalla Siege
    time limit per test
    2 seconds
    memory limit per test
    256 megabytes
    input
    standard input
    output
    standard output

    Ivar the Boneless is a great leader. He is trying to capture Kattegat from Lagertha. The war has begun and wave after wave Ivar's warriors are falling in battle.

    Ivar has nn warriors, he places them on a straight line in front of the main gate, in a way that the ii-th warrior stands right after(i1)(i−1)-th warrior. The first warrior leads the attack.

    Each attacker can take up to aiai arrows before he falls to the ground, where aiai is the ii-th warrior's strength.

    Lagertha orders her warriors to shoot kiki arrows during the ii-th minute, the arrows one by one hit the first still standing warrior. After all Ivar's warriors fall and all the currently flying arrows fly by, Thor smashes his hammer and all Ivar's warriors get their previous strengths back and stand up to fight again. In other words, if all warriors die in minute tt, they will all be standing to fight at the end of minute tt.

    The battle will last for qq minutes, after each minute you should tell Ivar what is the number of his standing warriors.

    Input

    The first line contains two integers nn and qq (1n,q2000001≤n,q≤200000) — the number of warriors and the number of minutes in the battle.

    The second line contains nn integers a1,a2,,ana1,a2,…,an (1ai1091≤ai≤109) that represent the warriors' strengths.

    The third line contains qq integers k1,k2,,kqk1,k2,…,kq (1ki10141≤ki≤1014), the ii-th of them represents Lagertha's order at the ii-th minute: kiki arrows will attack the warriors.

    Output

    Output qq lines, the ii-th of them is the number of standing warriors after the ii-th minute.

    Examples
    input
    Copy
    5 5
    1 2 1 2 1
    3 10 1 1 1
    output
    3
    5
    4
    4
    3
    input
    4 4
    1 2 3 4
    9 1 10 6
    output
    1
    4
    4
    1
    Note

    In the first example:

    • after the 1-st minute, the 1-st and 2-nd warriors die.
    • after the 2-nd minute all warriors die (and all arrows left over are wasted), then they will be revived thus answer is 5 — all warriors are alive.
    • after the 3-rd minute, the 1-st warrior dies.
    • after the 4-th minute, the 2-nd warrior takes a hit and his strength decreases by 1.
    • after the 5-th minute, the 2-nd warrior dies.

     这题其实就是一个前缀和二分查找。

     1 #include <cstdio>
     2 #include <algorithm>
     3 #include <vector>
     4 #include <queue>
     5 #include <cstring>
     6 #include <string>
     7 using namespace std;
     8 const int maxn = 2e5 + 10;
     9 long long a[maxn], b[maxn], sum[maxn], sum1[maxn];
    10 int main() {
    11     long long n, q;
    12     while(scanf("%lld%lld", &n, &q) != EOF) {
    13         sum[0] = 0;
    14         for (long long i = 1 ; i <= n ; i++) {
    15             scanf("%lld", &a[i]);
    16             sum[i] = sum[i - 1] + a[i];
    17         }
    18         for (long long i = 1 ; i <= q ; i++) {
    19             scanf("%lld", &b[i]);
    20         }
    21         long long temp = 0, cnt, ret = 0;
    22         for (long long i = 1 ; i <= q ; i++) {
    23             cnt = upper_bound(sum + 1, sum + n + 1, sum[temp] + b[i] + ret) - sum - 1;
    24             ret = a[cnt + 1] - (sum[cnt + 1] - sum[temp] - b[i] - ret);
    25             if (ret == a[cnt + 1]) ret = 0;
    26             temp = cnt;
    27             if (temp == n  )  {
    28                 temp = 0;
    29                 ret = 0;
    30             }
    31             printf("%lld
    ", n - temp);
    32         }
    33     }
    34     return 0;
    35 }
    View Code
  • 相关阅读:
    三角形的最大周长
    Java 虚拟机运行时数据区详解
    四数相加 II
    Java 注解详解
    四因数
    【论文笔记+复现踩坑】End-to-end Recovery of Human Shape and Pose(CVPR 2018)
    假如 Web 当初不支持动态化
    保姆级干货分享
    C# ±180的值转成0-360
    C# 校验算法小结
  • 原文地址:https://www.cnblogs.com/qldabiaoge/p/8983716.html
Copyright © 2011-2022 走看看