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  • POJ 2955 Brackets 区间DP 最大括号匹配

    http://blog.csdn.net/libin56842/article/details/9673239

    http://www.cnblogs.com/ACMan/archive/2012/08/09/2630497.html

    http://blog.csdn.net/chaiyuan414/article/details/5448699

    #include <iostream>
    #include <string>
    #include <cstring>
    #include <cstdlib>
    #include <cstdio>
    #include <cmath>
    #include <algorithm>
    #include <stack>
    #include <queue>
    #include <cctype>
    #include <vector>
    #include <iterator>
    #include <set>
    #include <map>
    #include <sstream>
    using namespace std;
    
    #define mem(a,b) memset(a,b,sizeof(a))
    #define pf printf
    #define sf scanf
    #define spf sprintf
    #define pb push_back
    #define debug printf("!
    ")
    #define INF 10000
    #define MAX(a,b) a>b?a:b
    #define blank pf("
    ")
    #define LL long long
    #define ALL(x) x.begin(),x.end()
    #define INS(x) inserter(x,x.begin())
    #define pqueue priority_queue
    
    const int MAXN = 1000 + 5;
    
    int n,m;
    
    int dp[110][110];
    char a[110];
    
    int main()
    {
        int i,j;
        while(sf("%s",a)==1 && a[0]!='e')
        {
            n = strlen(a);
            mem(dp,0);
            for(int l = 1;l<n;l++)
            {
                for(i=0;i<n-l;i++)
                {
                    j = i+l;
                    if((a[i]=='(' && a[j]== ')') || (a[i]=='[' && a[j]== ']'))
                        dp[i][j] = dp[i+1][j-1]+2;
    
                    for(int k =i+1;k<j;k++)
                    {
                        dp[i][j] = max(dp[i][j],dp[i][k]+dp[k+1][j]);
                    }
    
                }
            }
            pf("%d
    ",dp[0][n-1]);
        }
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/qlky/p/5454325.html
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